All categories

3 years ago

How does hydrogen bonding affect water molecules

1 answer:

4 0

Since the oxygen likes to hog all the electrons, it gives the hydrogen molecules a slight positive charge and the itself a slightly negative charge.
Positive attracts negative, so there is some sort of attraction between water molecules, though a weak one.

You might be interested in

What is the mass of 0.257 mol of calcium nitrate?

poizon [28]

Answer: 42.14 g

Explanation: calcium nitrate - $Ca(NO_{3} )_{2}$

, the molar mass of calcium nitrate = 164 g

<h3> formula used = $given mass/molar mass$ = no of moles </h3>

mass required = $0.257*164$

= $42.14$ g

4 0

1 year ago

Hydrocarbons separated by fractional distillation of petroleum can be cracked to make

lana66690 [7]

Answer:

c.hg cannot be cracked for fractional distillation as there is only one of each

Explanation:

8 0

3 years ago

Which is an unreliable source?

vodomira [7]

Answer:

I believe CDC I s the most reliable

6 0

3 years ago

Match the salt with the acid and base used to form it in a neutralizing reaction. K2SO4

emmasim [6.3K]

Answer:

KOH and H₂SO₄

Explanation:

Neutralization reaction:

It is the reaction in which acid and base react with each other and produce salt and water.

For example:

2KOH + H₂SO₄ → K₂SO₄ + 2H₂O

1. Potassium hydroxide and sulfuric acid react to produce potassium sulfate salt and water.

2. Potassium hydroxide and phosphoric acid react to produce potassium phosphate and water.

H₃PO₄ + 3KOH → K₃PO₄ + 3H₂O

3. Phosphoric acid sodium hydroxide react to produce sodium phosphate and water.

H₃PO₄ + 3NaOH → Na₃PO₄ + 3H₂O

3 0

3 years ago

Read 2 more answers

A horizontal cylinder equipped with a frictionless piston contains 785 cm3 of steam at 400 K and 125 kPa pressure. A total of 83

guapka [62]

Answer:

a. 478.69 K

b. 939.43 $cm^{3}$

c. 19.30 J

d. 64.5J

Explanation:

From the question, we can identify the following;

$V_{o}$ = 785 $cm^{3}$ = 0.000785 $m^{3}$

$T_{o}$ = 400K

$P_{o}$ = 125 Kpa = 125 000 Pa

Using the ideal gas equation,

PV = nRT

where R is the molar gas constant = 8.314 $m^{3}$ ⋅Pa⋅ $K^{-1}$ ⋅ $mol^{-1}$

Thus, n = PV/RT = (125000 × 0.000785)/(8.314 × 400) = 0.03 mol

a. Steam temperature in K

To calculate this, we use the constant pressure process;

q = nΔH

Where q is 83.8J according to the question

Thus;

83.8 = 0.03 × [34980 + 35.5 $T_{1}$ - (34980 + 35.5 $T_{o}$ )]

83.8 = (0.03 × 35.5) ( $T_{1}$ - 400K)

83.8 = 1.065 ( $T_{1}$ - 400)

78.69 = ( $T_{1}$ - 400)

$T_{1}$ = 400 + 78.69

$T_{1}$ = 478.69 K

b. Final cylinder volume

To calculate this, we make use of the Charles' law(Temperature and pressure are directly proportional)

$V_{1}$ / $T_{1}$ = $V_{o}$ / $T_{o}$

$V_{1}$ = $V_{o}$ $T_{1}$ / $T_{o}$

$V_{1}$ = (785 × 478.69)/400

$V_{1}$ = 939.43 $cm^{3}$

c. Work done by the system

Mathematically, the work done by the system is calculated as follows;

w = P( $V_{1}$ - $V_{o}$ ) = 125 KPa ( 939.43 - 785) = 19.30 J

d. Change in internal energy of the steam in J

ΔU = q - w = 83.8 - 19.3 = 64.5J

6 0

3 years ago