Answer:
The journal entry would be:
Explanation:
Note: Options are missing so providing the journal entry.
The journal entry would be for recording the collection of the note is:
October 30
Cash A/c.........................Dr $10,150
Interest Revenue A/c.........Cr $150
Notes Receivable A/c.........Cr $10,000
On October 30, the amount is collected so the any increase in cash is debited. Therefore, cash account is debited. And it is collected against a notes Receivable of $10,000 so it leads to decrease in liability, it is credited. Therefore, the notes receivable is credited. And the interest revenue is credited.
A year has two semesters, then
n = 2<span>v(t)=p<span><span>(<span>1+<span>r/2</span></span>)</span><span>2t
</span></span></span><span>
3875.79 = 1900∗<span><span>(<span>1+(<span>0.04/2)</span></span>)^</span><span>2t
</span></span></span><span>
2.0398895 = <span><span>(<span>1+<span>0.042</span></span>)^</span><span>2t
</span></span></span>Apply natural logarithm on both sides
<span>ln(2.0398895) = ln<span>[<span><span>(<span>1+<span>0.042</span></span>)^</span><span>2t</span></span>]
Then simplify,
</span></span><span>0.712896 = 2t∗ln(1.02)
</span><span>t = <span>0.712896 / (<span>2∗ln(1.02))
</span></span></span><span><span>
t=18 years
I hope my answer helped you. Have a nice day!</span></span>
Answer:
A) sample size = 23.475 ≈ 23
B) How to tell someone to do the test is by taking a sampling process of a lot of the products because this will help to figure out defective units in the line of production and also ensure that the quality of the products are up to the same quality required
Explanation:
Data given
AQL = 20%, = 0.2
LTPD = 52% = 0.52
Assuming consumer risk acceptable by company = 10%
producer risk = 5%
A) First we calculate the ratio
= LTPD / AQL = 0.52 / 0.2 = 2.6
from the table of LTPD/AQL 2.6 is closest to 2.768
to calculate the sample size we apply the formula from the exhibit table
n ( AQL ) = 4.695
Therefore n ( sample size ) = 4.695 / 0.2 = 23.475
B) How to tell someone to do the test is by taking a sampling process of a lot of the products because this will help to figure out defective units in the line of production and also ensure that the quality of the products are up to the same quality required
Answer:
$69.41
Explanation:
Given that
D1 = 4.75
D2 = 5.25
D3 = 5.75
D4 = 7
g = 7% or 0.07
R = 15% or 0.15
Therefore,
D5 = D4 (1 + g)
= 7 × 1.07
= 7.49
Also,
P4 = D5/g × R
= 7.49/0.15 × 0.07
= 93,625
Thus,
P0 = 4.75/1.15 + 5.25/(1.15)^2 + 5.75/(1.15)^3 + 7/(1.15)^4 + 93.625/(1.15)^4
= $ 69.41357
Approximately
= $ 69.41
Answer:
While taking courses at a community college, Patrice also spends time each week assisting at her town’s community center. Patrice aides the community center leaders and learns about how the center works. Although she is not paid for this time, she hopes to begin a full-time job at the community center after finishing her courses. Patrice’s time at the community center is called
Explanation:
D. an internship
