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2 years ago

I NEED HELP ASAP!! What is the difference between the experimental group and a control group?

1 answer:

3 0

I believe the control group is what doesn't change in the experiment, and the experimental group is what is being tested / receives the treatment :)

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A piece of unknown metal with mass 68.6 g is heated to an initial temperature of 100 °C and dropped into 42 g of water (with an

kogti [31]

The piece of unknown metal is in thermal equilibrium with water such that Q of metal is equal to Q of the water. We write this equality as follows:

-Qm = Qw

Mass of metal (Cm)(ΔT) = Mass of water (Cw) (ΔT)

where C is the specific heat capacities of the materials.

We calculate as follows:

-(Mass of metal (Cm)(ΔT)) = Mass of water (Cw) (ΔT)

-68.6 (Cm)(52.1 - 100) = 42 (4.184) (52.1 - 20)

Cm = 1.717 -----> OPTION C

8 0

3 years ago

To make a Br2 bond, how many total valence electrons are required?

lapo4ka [179]

Answer:

2. 14

Explanation:

To form Br₂ bond, a total of 14 electrons are needed.

Bromine is an element in the 7th group on the periodic table. It has 7 valence electrons.

In forming the bromine gas, the two atoms of bromine shares 7 electrons each.
These electrons are from their outermost shell.
The outermost shell is the valence shell.
So, two atoms donating 7 electrons gives 14 electrons.

6 0

3 years ago

What happens when nitrogen fills its valence shell?

RSB [31]

Hello!

Like many other elements in chemistry, when an atom's valence shell is filled the element becomes stable. Through the octet rule we know that when the very last valence shell becomes filled, the atom is stable and therefore it is highly unlikely for the element to form bonds with that of another.

I hope this helped!

8 0

3 years ago

What is the percent yield of NaCl if 31g of CuCl2 reacts with excess NaNo3 to produce 21.2g of NaCl

Valentin [98]

The answer is 78.7% yield.

3 0

3 years ago

How many atoms are in 10.1 g Ne

LekaFEV [45]

Answer:

3.01 × 10²³ atoms Ne

General Formulas and Concepts:

Atomic Structure

Reading a Periodic Tables
Moles

Stoichiometry

Using Dimensional Analysis

Explanation:

Step 1: Define

Identify

[Given] 10.1 g Ne

[Solve] atoms Ne

Step 2: Identify Conversions

Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

[PT] Molar Mass of Ne: 20.18 g/mol\

Step 3: Convert

[DA] Set up: $\displaystyle 10.1 \ g \ Ne(\frac{1 \ mol \ Ne}{20.18 \ g \ Ne})(\frac{6.022 \cdot 10^{23} \ atoms \ Ne}{1 \ mol \ Ne})$
[DA] Divide/Multiply [Cancel out units]: $\displaystyle 3.01398 \cdot 10^{23} \ atoms \ Ne$

Step 4: Check

Follow sig fig rules and round. We are given 3 sig figs.

3.01398 × 10²³ atoms Ne ≈ 3.01 × 10²³ atoms Ne

4 0

3 years ago

I NEED HELP ASAP!! What is the difference between the experimental group and a control group?​

I NEED HELP ASAP!! What is the difference between the experimental group and a control group?