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2 years ago

With the aid of a balanced chemical equation explain Chemical Reactions and the Types Of Chemical Reaction

Chemistry

1 answer:

e-lub [12.9K]2 years ago

6 0

Answer:

Answers

1.)reactants: nitrogen and hydrogen; product: ammonia.

2.)reactants: magnesium hydroxide and nitric acid; products: magnesium nitrate and water.

3.)N 2 + 3H 2 → 2NH 3

4.)Mg(OH) 2 + 2HNO 3 → Mg(NO 3) 2 + 2H 2O.

5.)2NaClO 3 → 2NaCl + 3O 2

6.)4Al + 3O 2 → 2Al 2O 3

7.)N 2(g) + 3H 2(g) → 2NH 3(g)

Explanation:

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A balloon containing helium gas expands from 230

Anit [1.1K]

The answer for the following problem is mentioned below.

Therefore the final moles of the gas is 14.2 × $10^{-4}$ moles.

Explanation:

Given:

Initial volume ( $V_{1}$ ) = 230 ml

Final volume ( $V_{2}$ ) = 860 ml

Initial moles ( $n_{1}$ ) = 3.8 × $10^{-4}$ moles

To find:

Final moles ( $n_{2}$ )

We know;

According to the ideal gas equation;

P × V = n × R × T

where;

P represents the pressure of the gas

V represents the volume of the gas

n represents the no of the moles of the gas

R represents the universal gas constant

T represents the temperature of the gas

So;

V ∝ n

$\frac{V_{1} }{V_{2} }$ = $\frac{n_{1} }{n_{2} }$

where,

( $V_{1}$ ) represents the initial volume of the gas

( $V_{2}$ ) represents the final volume of the gas

( $n_{1}$ ) represents the initial moles of the gas

( $n_{2}$ ) represents the final moles of the gas

Substituting the above values;

$\frac{230}{860}$ = $\frac{3.8 * 10^-4}{n_{2} }$

$n_{2}$ = 14.2 × $10^{-4}$ moles

Therefore the final moles of the gas is 14.2 × $10^{-4}$ moles.

7 0

3 years ago

Oh really How do I look evil, right? Egypt made me brown

olasank [31]

Answer:

ummmmmmmmmmmmmmmmmmmmmmmm

8 0

2 years ago

Read 2 more answers

What is the reactant of 2Fe2O3 = 4Fe + 3O2

Anit [1.1K]

It depends on the direction of the arrow.

If the arrow goes like this ---> the reactant would be 2Fe2O3

If the arrow goes like this <--- the reactants would be 4Fe + 3O2

3 0

3 years ago

Which one of the following exhibits dipole-dipole attraction between molecules?

KiRa [710]

Answer:

Anything that has polar covalent bonds exhibit dipole-dipole attraction between molecules.

Explanation:

Since, you do not have the options, you can determine the answer by knowing that anything that has polar covalent bonds exhibit dipole-dipole attraction between molecules.

7 0

3 years ago

Put this equation into word form.

Mars2501 [29]

Answer:

Explanation:

symbol of postassium is k and there is no symbol k. so i guess no2

7 0

2 years ago