Answer:
28.1
Explanation:
Divide the percentage abundances by 100:
92.2% ÷ 100 = 0.922
4.7% ÷ 100 = 0.047
3.1% ÷ 100 = 0.031
multiply them by their corresponding mass number:
0.922×28 = 25.816
0.047×29 = 1.363
0.031×30 = 0.93
add them all together to get your final answer:
25.816 + 1.363 + 0.93 = 28.109
to one decimal place:
28.1
I hope that helps!!!
The concentration of the HBr would be 0.09 M
<h3>What are stoichiometric problems?</h3>
First, let us look at the equation of the reaction:
The mole ratio of HBr to NaOH is 1:1.
Mole of 15 mL, 0.30 M NaOH = 0.30 x 15/1000 = 0.0045 moles
Equivalent mole of HBr - 0.0045 moles
Molarity of HBr = mole/volume = 0.0045/50/1000 = 0.09 M
More on stoichiometric problems can be found here: brainly.com/question/15047541
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Answer:
20.91% of the hydrated calcium sulfate salt is water
Explanation:
<u>Step1</u> : Calculate the mass of H2O that evaporated
A hydrated salt has a mass of 1.803g. After heating at 170° C, this means water will evaporate, the mass of the salt is 1.426g
The difference is water that evaporated.
⇒Mass H2O of hydration =1.803 g - 1.426g g = 0.377 g H2O
<u>Step 2</u>: Calculate the % of water in the hydrated calcium sulfate salt
⇒ mass of H2O = 0.377g
⇒ mass of calcium sulfate salt = 1.803g
⇒ % water in the calcium sulfate salt = (0.377 / 1.803) x 100% = 20.91%
20.91% of the hydrated calcium sulfate salt is water
They are performed in the JEJUNUM
Answer:
See explanation
Explanation:
In each chlorine atom, there are seven valence electrons. Recall that each chlorine atom only needs one electron in order to achieve the stable octet structure.
As a result of this, the chlorine atoms in Cl2 share two electrons contributed by each of the bonding atoms. By so doing, each atom achieves the stable octet as required by the octet rule.