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Minchanka [31]
3 years ago
9

Write down the number eleven thousand,eleven hundred and eleven in figures

Mathematics
1 answer:
Tomtit [17]3 years ago
3 0

Answer:

12,111

Step-by-step explanation:

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How do I factor . X2 { squared } -9x+28?
Dmitrij [34]
It is not factorable
3 0
3 years ago
9x^2 - 8x - 1 = 0<br> What are the x intercepts?
sasho [114]
9x^2  - 8x - 1 = 0

(9x + 1(x - 1) = 0

x = -1/9 , 1  

x intercepts are -1/9 and 1.
4 0
3 years ago
the number n is a 2-digit number. when n i divided by 10, the remainder is 9, and when n is divided by 9, the remainder is 8. wh
larisa [96]
Think of numbers that when they are divided by 10, the remainder is 9.
So numbers like: 19, 29, 39, 49, 59, 69, 79, 89, and 99.

Now numbers that when they are divided by 9, the remainder is 8.
So numbers like: 17, 26, 35, 44, 53, 62, 71, 80, 89, and 98.

Now the number that is alike from the two sets of numbers is n.
n=89

Double check your work.
Divide 89 by 10. Remainder of 9
Divide 89 by 9. Remainder of 8.

Hope this helps :)

6 0
3 years ago
The function represented by the table has the form y =acos(bx). Which of the following statements are tru
nlexa [21]

Answer:

It's A C & D

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
The populations of two cities after t years can be modeled by -150t+50,000 and 50t+75,000 . What is the difference in the popula
creativ13 [48]

Answer:

The difference in the populations of the cities when t=4 is 25,800.

Step-by-step explanation:

Given equations each of the city:

-150t+50,000

and

50t+75,000

To find the difference between the population when t=4, we first have to solve both equation when t=4.

For both equations, substitute 4 into t:

-150(4) + 50,000 = 49,400

50(4) + 75,000 = 75,200

Now subtract 49,400 from 75,200 and you get 25,800.

The difference in the populations of the cities when t=4 is 25,800.

3 0
2 years ago
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