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3 years ago

Difference betwwen Accleration and retradation

Physics

1 answer:

BartSMP [9]3 years ago

6 0

I’m pretty sure one increases just straight up velocity and the other is kind of a deceleration

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What happens as a result of an increase in the intensity of a sound wave?

larisa [96]

As the intensity increases the energy increases.

Answer:

C. the energy of the sound wave increases

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3 years ago

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Find the radius R of the orbit of a geosynchronous satellite that circles the earth. (Note that R is measured from the center of

laila [671]

Answer:

R^3 = GM / ω^2

R^3 = (6.67 * 10^-11) * (5.98 * 10^24) / (0.00007272)^2

R^3 = 7.54 * 10^22

R = 42,251,269

R = 4.225 * 10^7 m

4.225 * 10^7

Explanation:

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3 years ago

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If the velocity of a pitched ball has a magnitude of 47.0 m/s and the batted ball's velocity is 50.5 m/s in the opposite directi

Naya [18.7K]

Answer:

The magnitude of change in momentum of the ball is $97.5 m$ and impulse is also $97.5 m$

Explanation:

Given:

Velocity of a pitched ball $v _{i} = 47$ $\frac{m}{s}$

Velocity of ball after impact $v_{f} = -50.5$ $\frac{m}{s}$

From the formula of change in momentum,

$\Delta P = m (v_{f} -v_{i} )$

Here mass is not given in question,

Mass of ball is $m$

Change in momentum is given by,

$\Delta P = m (-50.5 -47)$

$\Delta P = -97.5 m$

Magnitude of change in momentum is

$\Delta P = 97.5 m$

And impulse is given by

$J = \Delta P$

$J = -97.5 m$

So impulse and

Therefore, the magnitude of change in momentum of the ball is $97.5 m$ and impulse is also $-97.5 m$

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3 years ago

A boat is moving due east in a region where the earth's magnetic field is 5.0×10⁻⁵ NA⁻¹ m⁻¹ due north and horizontal. The boat c

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Answer: Induced emf is given by:

ε= Bvl

On putting the values we get

=5×10

−5

×1.50×2

=0.15mV

Explanation:

Hope these helped have a wonderful Christmas break ❄️

7 0

3 years ago

If v lies in the first quadrant and makes an angle Ï/3 with the positive x-axis and |v| = 4, find v in component form.

Alexeev081 [22]

Answer:

$v=$

Explanation:

We are given that

Magnitude of vector v= $\mid v\mid =4$

v lies in the first quadrant

$\theta=\frac{\pi}{3}$

$v_x=\mid v\mid cos\theta$

$v_y=\mid v\mid sin\theta$

Substitute the values then we get

$v_x=4cos\frac{\pi}{3}$

$v_x=4\times \frac{1}{2}=2$

$cos\frac{\pi}{3}=\frac{1}{2}$

$v_y=4\times sin\frac{\pi}{3}=4\times \frac{\sqrt 3}{2}=2\sqrt 3$

$sin\frac{\pi}{3}=\frac{\sqrt 3}{2}$

Therefore, the vector v in component form $=$

$v=$

4 0

4 years ago

Difference betwwen Accleration and retradation​

Difference betwwen Accleration and retradation