Answer:
The fringes are 4.7*10^-7 m apart, such that they are adjacent.
Explanation:
Using the formula for adjacent fringes given a single slit:
Δ
Δ
Δ
Hope this helps!
Answer:
The answer to your question is:
a) h max = 529.7 m
b) t = 20.4 s
c) t = 20.6 s
Explanation:
a) h max = -(vo)² / 2g
= 100² / 2(9.81)
= 10000 / 19.62
= 509.7 m
total height = 509.7 + 20 = 529.7 m
b)
h = gt² / 2
t = √ 2h / g
t = √ 2(509.7)/9.81
t = √ 103.91
t = 10.19 s
total time = 2 x t = 2 x 10.19 = 20.4 s
c)
h = vot + 1/2gt²
20 = 100t + 1/2(9.91) t²
4.9t² + 100 t -20 = 0 quadratic equation
t = 0.19 s
Total time = 0.19 + 20.4 = 20.6 s
The speed does the block move after it is hit by the bullet that remains stuck inside the block will be 23.7 m/sec and it takes 12.07 seconds to stop.
<h3>What is the law of conservation of momentum?</h3>
According to the law of conservation of momentum, the momentum of the body before the collision is always equal to the momentum of the body after the collision.
Apply the law of conservation of momentum principle;
m₁v₁+m₂v₂cosΘ =(m₁+m₂)V
3 kg × 12 m/s + 0,1 kg × 400 m/s cos 20° = (3+0.1)V
36 + 40 cos 20° = 3.1 V
V=23.7 m/sec
The time it takes to stop when the friction coefficient between the block and the surface is 0.2 is found as;
V = u +at
V = 0+ μgt
23..7=0.2× 9.81 ×t
t=12.07 sec
Hence, it takes 12.07 seconds to stop.
To learn more about the law of conservation of momentum refer;
brainly.com/question/1113396
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some massive black dwarfs may eventually produce <u>supernova explosions. </u>These will occur if pycnonuclear (density-based) fusion processes much of the star to iron, which would lower the Chandrasekhar limit for some black dwarfs below their actual mass.
