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3 years ago

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2. (Work-Energy Theorem) A watermelon of mass m is dropped from rest from the roof of a building of height h and feels no air re

sistance. a. What is the work done by gravity on the watermelon from the roof to the ground? b. What is the kinetic energy of the watermelon just as it hits the ground? c. What is the speed of the watermelon just as it hits the ground? d. Which answer(s) above will change if there is appreciable air resistance? m = 4.80 kg h = 25.0 m

1 answer:

andreyandreev [35.5K]3 years ago

5 0

Answer:

SORRY SISO REALLY DON'T KNOW ANS SORRY!........☹☹☹

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The flow of air from an ocean or lake to the land is called a ___________________________.

slava [35]

Maybe sea or onshore breeze

It develops due to the difference of air pressure greater by the different temperature of the water and land

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3 years ago

A particle with mass 1.09 kg oscillates horizontally at the end of a horizontal spring. A student measures an amplitude of 0.985

e-lub [12.9K]

Answer:

a) $f = 0.598\,hz$ , b) $v_{max} = 3.701\,\frac{m}{s}$ , c) $k = 15.385\,\frac{N}{m}$ , d) $U = 1.081\,J$ , e) $K = 6.382\,J$ , f) $v\approx 3.422\,\frac{m}{s}$

Explanation:

a) The frequency of oscillation is:

$f = \frac{76}{127\,hz}$

$f = 0.598\,hz$

b) The angular frequency is:

$\omega = 2\pi \cdot f$

$\omega = 2\pi \cdot (0.598\,hz)$

$\omega = 3.757\,\frac{rad}{s}$

Lastly, the speed at the equilibrium position is:

$v_{max} = \omega \cdot A$

$v_{max} = (3.757\,\frac{rad}{s} )\cdot (0.985\,m)$

$v_{max} = 3.701\,\frac{m}{s}$

c) The spring constant is:

$\omega = \sqrt{\frac{k}{m}}$

$k = \omega^{2}\cdot m$

$k = (3.757\,\frac{rad}{s} )^{2}\cdot (1.09\,kg)$

$k = 15.385\,\frac{N}{m}$

d) The potential energy when the particle is located 38.1 % of the amplitude away from the equilibrium position is:

$U = \frac{1}{2}\cdot (15.385\,\frac{N}{m} )\cdot (0.375\,m)^{2}$

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e) The maximum potential energy is:

$U_{max} = \frac{1}{2}\cdot (15.385\,\frac{N}{m} )\cdot (0.985\,m)^{2}$

$U_{max} = 7.463\,J$

The kinetic energy when the particle is located 38.1 % of the amplitude away from the equilibrium position is:

$K = U_{max} - U$

$K = 7.463\,J - 1.081\,J$

$K = 6.382\,J$

f) The speed when the particle is located 38.1 % of the amplitude away from the equilibrium position is:

$K = \frac{1}{2}\cdot m \cdot v^{2}$

$v = \sqrt{\frac{2\cdot K}{m} }$

$v = \sqrt{\frac{2\cdot (6.382\,J)}{1.09\,kg} }$

$v\approx 3.422\,\frac{m}{s}$

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3 years ago

On a frictionless plane inclined at angle 303. The box is connected via a cord of negligible mass to a box of laundered money (m

KATRIN_1 [288]

Answer:

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3 years ago

Some help please ,.......

serious [3.7K]

It's c bro, .2x5 equals 1, which accounts for the 1m/s accelerations.

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4 years ago

Read 2 more answers

How is budgeting different for most states than for the federal government?

meriva

There are three general kinds of state balanced budget requirements:

<span>The governor's proposed budget must be balanced (43 states and Puerto Rico).The budget the legislature passes must be balanced (39 states and Puerto Rico).<span>The budget must be balanced at the end of a fiscal year or biennium, so that no deficit can be carried forward (37 states and Puerto Rico).
</span></span><span>Nature of state balanced-budget requirements All the states except Vermont have a legal requirement of a balanced budget. Some are constitutional, some are statutory, and some have been derived by judicial decision from constitutional provisions about state indebtedness that do not, on their face, call for a balanced budget. The General Accounting Office has commented that "some balanced budget requirements are based on interpretations of state constitutions and statutes rather than on an explicit statement that the state must have a balanced budget."

hope that helped, please mark me as brainliest

</span>

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3 years ago