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nikklg [1K]
3 years ago
10

2. (Work-Energy Theorem) A watermelon of mass m is dropped from rest from the roof of a building of height h and feels no air re

sistance. a. What is the work done by gravity on the watermelon from the roof to the ground? b. What is the kinetic energy of the watermelon just as it hits the ground? c. What is the speed of the watermelon just as it hits the ground? d. Which answer(s) above will change if there is appreciable air resistance? m = 4.80 kg h = 25.0 m​
Physics
1 answer:
andreyandreev [35.5K]3 years ago
5 0

Answer:

SORRY SISO REALLY DON'T KNOW ANS SORRY!........☹☹☹

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Why is it so important to follow classroom procedures?
Aleks [24]
Maybe because you will get in trouble if u don't follow them. I never follow classroom procedures and I'm in trouble all the time
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3 years ago
A. What is the S.l unit of acceleration?<br>m<br>m/s o<br>m/s2<br>N​
kifflom [539]

Explanation:

The SI unit of acceleration is the metre per second squared (m s−2); or "metre per second per second", as the velocity in metres per second changes by the acceleration value, every second.

8 0
3 years ago
Problem 2: (15 pts) A 10-m high cylindrical container is half-filled at the bottom with water of density =1000 kg/m3 while the t
Step2247 [10]

Answer:

\Delta p = 90.7 kPa

Explanation:

specific gravity of oil is = \frac{\rho_{oil}}{\rho_w}

\rho_{oil} = 0.85*1000 = 850 kg/m3

we know that

change in pressure  for oil is given as

\Delta p = \rho gh

here density and h is for oil

\Delta p = 850*5 *9.81 = 41,692.5 kPa

change in pressure  for WATER is given as

\Delta p = \rho gh

here density is for water and h is for water

\Delta p = 1000*5 *9.81 = 49,050 kPa

pressure change due to both is given as

\Delta p = 41692.3 + 49050 = 90742.5 N/m2

\Delta p = 90.7 kPa

8 0
3 years ago
Read 2 more answers
The speed that a tsunami can travel is modeled by the equation , where s is the speed in kilometers per hour and d is the averag
CaHeK987 [17]

The speed of tsunami is a.0.32 km. 

Steps involved  :

The equation s = 356d models the maximum speed that a tsunami can move at. It reads as follows: s = 200 km/h d =?

Let's now change s to s in the equation to determine d: s = 356√d 200 = 356√d √d = 200 ÷ 356 √d = 0.562 Let's square the equation now by squaring both sides: (√d)² = (0.562) ² d = (0.562)² = 0.316 ≈ 0.32

As a result, 0.32 km is roughly the depth (d) of water for a tsunami moving at 200 km/h.

To learn more about tsunami refer : brainly.com/question/11687903

#SPJ4

6 0
2 years ago
The mass number is determined by which particles?
BartSMP [9]
I am not completely sure, but I believe that it depends on the total mass of the Protons and Neutrons




7 0
3 years ago
Read 2 more answers
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