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LenKa [72]
3 years ago
15

If the radius of Earth were one half what it is now, and the mass were the same, what would be the value of g?

Physics
2 answers:
Inessa [10]3 years ago
6 0

Answer:

4g

Explanation:

the equation of g (field gravity)

g = G M/R²

because G (Contant of Gravitasion) and M (Mass of earth) same, them

g2/g1 = R1²/R2²

g1 = g now

g2 = g which the value we looking for

g2/g = 1/(1/2)²

g2/g = 1/(1/4)

g2/g = 4

g2 = 4g

mel-nik [20]3 years ago
5 0

Answer:

4 times what it is now.

Explanation:

g=G(M/r^2)

G is constant, so ignore.

We have (1M/0.5r^2), or 4.

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Read 2 more answers
Two capillary tubes, made of the same substance, are lowered into a water bath. The radius of the larger tube is twice that of t
Alinara [238K]

Answer: 4.4 cm.

Explanation:

Rise of water in the smaller tube= h1=8.8 centimeter(cm)

Radius of the smaller tube= r

Rise of water in the larger tube= h2 (in centimeter).

The radius of the larger tube is twice that of the smaller tube means that;

The radius in the larger tube is 2r ( 2 multiply by the radius r, of the smaller tube)

Using Jurin's law;

height or rise of liquid is inversely proportional to its radius, r.

That is; hr= constant.

Therefore, we have;

h1 × r1 = h2 × r2.

Rise in smaller tube × radius of the smaller tube = height of the larger tube × radius of the larger tube.

8.8 cm × r = h2 × 2r

= (8.8cm)r = (h2) 2r

Divide both sides by 2r, we then have;

8.8cm r/ 2r = h2

h2= 4.4cm

Therefore, the height or rise in large tube is half of that of the smaller tube.

8 0
3 years ago
A metallic conductor has a resistivity of 35 × 10 −6 Ω⋅m. What is the resistance of a piece that is 20 m long and has a uniform
Nitella [24]

Answer:

Therefore the resistance of the conductor is 175Ω

Explanation:

Resistance:

  • Resistance of a metallic conductor is directly proportional to its length(l).
  • Resistance of a metallic conductor is inversely proportional to its cross section area(A).

The notation sign of resistance is R.

The unit of resistance is ohm (Ω).

Therefore,

R \propto l

and

R \propto \frac{1}{A}

\therefore R\propto \frac{l}{A}

\Rightarrow R=\rho \frac{l}{A}

ρ is the proportional constant.

It is also known as resistivity of that metal.

Given ρ=35×10⁻⁶Ω-m

l= 20 m

A= 4.0×10⁻⁶m²

\therefore R=35\times 10^{-6}\times \frac{20}{4.0\times 10^{-6}}

       =175Ω

Therefore the resistance of the conductor is 175Ω

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