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fenix001 [56]
2 years ago
13

A proton traveling due west in a region that contains only a magnetic field experiences a vertically upward force (away from the

surface of the earth). What is the direction of the magnetic field?
Physics
1 answer:
Vikki [24]2 years ago
3 0

South

Explanation:

The magnetic force F on a point charge moving with a velocity v in the presence of a magnetic field B is given by

\vec{\textbf{F}} = q\vec{\textbf{v}}\textbf{×}\vec{\textbf{B}}

and according to the right-hand rule, an upward magnetic force on a proton moving westward is only possible if the magnetic field is directed southward.

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When a 5.0kg cart undergoes a 2.2m/s increase in speed, what is the impulse of the cart
Karolina [17]

Answer:

11.0 kg m/s

Explanation:

The impulse exerted on the cart is equal to its change in momentum:

I=\Delta p=m\Delta v

where

m = 5.0 kg is the mass of the cart

\Delta v=2.2 m/s is its change in speed

Substituting numbers into the equation, we find

I=(5.0kg)(2.2 m/s)=11 kg m/s

7 0
3 years ago
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When is the pressure of the man on the ground more – lying position or standing position? Explain.
Dmitrij [34]
It is without a doubt in standing position!
“I will explain if u ask”
(Please mark brainlest if I helped u a bit)
3 0
2 years ago
What mineral is most abundant in granite
77julia77 [94]
I believe it would be orthoclase feldspar, quartz, micas, and amphiboles are the most abundant in granite.<span />
3 0
3 years ago
Ciara is swinging a 0.015 kg ball tied to a string around her head in a flat, horizontal circle. The radius of the circle is 0.5
Marat540 [252]

Answer:

Option C

Explanation:

From the question we are told that:

Mass m=0.015kg

Radius r=0.5m

Time t=0.70

Generally the equation for Tension is mathematically given by

 T=\frac{4mr}{t^2} \pi

 T=\frac{4*0.015*0.5}{(0.70)^2} (3.142)

 T=0.60N

Therefore

T=0.60 N, toward the center of the circle

Option C

3 0
3 years ago
A box is sliding down an incline tilted at a 12° angle above horizontal. The box is initially sliding down the incline at a spee
OLga [1]

Answer:

The box will cover a distance of 0.9199m before coming to rest

Explanation:

We are given;

Angle of tilt; θ = 12°

Speed of sliding down; u = 1.5 m/s

Coefficient of kinetic friction; μ = 0.34

We are told that the box is sliding down an incline tilted at a 12° angle above horizontal.

Thus,

The components of the weight of the block would be;

Fx = mg sinθ = mg sin 12

Fy = mg cosθ = mg cos 12

For, the normal force on the block, it will be counter balanced by the Y component of weight of block and so we have;

Normal force; Fn = mg cos 12

Now formula for the frictional force would be given by;

Ff = μmg cos 12

So, Ff = 0.34mg cos 12

So, the net force along the inclined plane is;

Fnet = Fx - Ff

Fnet = mg sin 12 - 0.34mg cos 12

Where Fnet = mass x acceleration.

Thus;

ma = mg sin 12 - 0.34mg cos 12

m will cancel out to give;

a = g sin 12 - 0.34g cos 12

a = 9.81(0.2079) - 0.34(9.81 × 0.9781)

a = -1.223 m/s²

According to Newton's equation of motion, we have;

(v² - u²) = 2as

s = (v² - u²)/2a

Final velocity is zero. Thus;

s = (0² - 1.5²)/(2 × -1.223)

s = -2.25/-2.446

s = 0.9199 m

Thus, the box will cover 0.9199m before coming to rest

4 0
3 years ago
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