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fenix001 [56]
3 years ago
13

A proton traveling due west in a region that contains only a magnetic field experiences a vertically upward force (away from the

surface of the earth). What is the direction of the magnetic field?
Physics
1 answer:
Vikki [24]3 years ago
3 0

South

Explanation:

The magnetic force F on a point charge moving with a velocity v in the presence of a magnetic field B is given by

\vec{\textbf{F}} = q\vec{\textbf{v}}\textbf{×}\vec{\textbf{B}}

and according to the right-hand rule, an upward magnetic force on a proton moving westward is only possible if the magnetic field is directed southward.

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In a hyrdo electic power plant the moving water turns the turbine creating ____________ energy.
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Answer:

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Explanation:

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Draw the position vs. time graph for a person walking at a constant speed of 1m/s for 10 seconds. On the same axes, draw graph f
Leto [7]
In both scenarios, the position - time graph will be a linear graph, since the speed is constant, so your position is moving at a consistent pace.
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3 years ago
What fraction of a piece of concrete will be submerged when it floats in mercury? the density of concrete is 2.3×103kg/m3 and de
chubhunter [2.5K]
<span>17% Any object that is floating will display the volume of fluid that matches the mass of the object that's floating. So if the object is 100% as dense as the fluid, it will just barely sink, if it's 50% as dense as the fluid, 50% will be submerged, etc. So let's see what percent of mercury's density is concrete. 2.3x10^3 / 13.6x10^3 = 0.169117647 = 16.9117647% Rounding to 2 significant figures gives 17%. So 17% of a piece of concrete will be submerged in mercury when it's floating in mercury.</span>
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3 years ago
What does Hooke's law say about the relationship of a spring to the force applied to it?
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Answer:

Explanation:Hooke's law states that " if the elastic limit of an elastic material is not exceeded, the extension,e is directly proportional to the applied force or load.

6 0
3 years ago
A small block of mass m = 0.032 kg can slide along the frictionless loop-the-loop, with loop radius R = 12 cm. The block is rele
Lunna [17]

Answer:

Part a)

W = 0.15 J

Part b)

W = 0.11 J

Part c)

U = 0.19 J

Part d)

U = 0.038 J

Part e)

U = 0.075 J

Part f)

It is independent of the speed of the object so all part answers will remain the same

Explanation:

Part a)

As we know that Point P is at height 5R while point Q is at height R

so the work done by gravity from P to Q is given as

W = mg(5R - R)

W = 0.032(9.8)(4)(0.12)

W = 0.15 J

Part b)

When it reaches to the top of the loop then its final height from ground is

h = 2R

so work done from P to Q is given as

W = mg(5R - 2R)

W = 3mgR

W = 0.11 J

Part c)

Potential energy at P point is given as

U = mgH

U = 0.032(9.8)(5)(0.12)

U = 0.19 J

Part d)

Potential energy at Q point is given as

U = mgH

U = 0.032(9.8)(0.12)

U = 0.038 J

Part e)

Potential energy at top point is given as

U = mgH

U = 0.032(9.8)(2)(0.12)

U = 0.075 J

Part f)

Since all the answer from part a) to part e) depends only upon the position of the object.

So here we can say that it is independent of the speed of the object so all part answers will remain the same

8 0
4 years ago
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