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balu736 [363]
2 years ago
6

WILL MARK BRAINLIEST:

Chemistry
1 answer:
Anastaziya [24]2 years ago
6 0

Answer:

Alienus

Explanation:

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Manganese, Mn, forms two ions, one with a 2+ charge and one with a 3+ charge. What is the formula for manganese (II) sulfide?
maria [59]
It would be MnSO4

The (II) lets you know it’s the form with a 2+ charge and Sulfate has a 2- charge

These will cancel out making it plain MnSO4

If it was manganese (iii) sulfide the answer would be Mn2(SO4)3
4 0
3 years ago
What are the other types of particles that make up a water particle?​
Neko [114]

Answer:Well, if you mean atoms, it has 2 Hydrogen atoms and 1 Oxygen.

Explanation:Water is H20 therefore, it has 2 Hydrogen atoms and 1 Oxygen. Water isn't made up of particles, they are made of atoms.

3 0
3 years ago
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Which of the following is a compound?<br> A. Zinc <br> B. S8 <br> C. CaCl2
sertanlavr [38]

C. Calcium is your best bet. Calcium chloride is amongst inorganic compounds.

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2 years ago
A reaction gives off 35.6 kJ how many calories is this?
tia_tia [17]
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7 0
2 years ago
Write the expression for the equilibrium constant for the reaction represented by the equation CaCO3(s)⇌Ca2+(aq)+CO32−(aq). Is K
Alexeev081 [22]

<u>Answer:</u> For the given reaction, the value of K_c is greater than 1

<u>Explanation:</u>

For the given chemical equation:

CaCO3(s)\rightleftharpoons Ca^{2+}(aq.)+CO_3^{2-}(aq.)

The expression of K_c for above equation follows:

K_c=\frac{[Ca^{2+}]\times [CO_3^{2-}]}{[CaCO_3}]\\\\K_c=[Ca^{2+}]\times [CO_3^{2-}]

The concentration of pure solids and pure liquids are taken as 1 in equilibrium constant expression

As, the denominator is missing and the numerator is the only part left in the expression. So, the value of K_c will be greater than 1.

Hence, for the given reaction, the value of K_c is greater than 1

5 0
3 years ago
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