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mamaluj [8]
2 years ago
12

What happens to the solar energy absorbed by plants during photosynthesis ?

Chemistry
2 answers:
zzz [600]2 years ago
7 0

Answer:

Photosynthesis in plants converts solar energy into chemical energy using electrons and protons from water. in plants involves a series of steps and reactions that use solar energy, water, and carbon dioxide to produce organic compounds and oxygen.

Explanation:

yarga [219]2 years ago
5 0

Answer:

its is used to make sugar which plants eat think it goes through like glycose or something

Explanation:

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Which of the following is the reason that the lemurs shown below share many traits?
ycow [4]
A. They have similar DNA
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3 years ago
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The condition of acidosis can also cause ____________ because the higher H concentration diffuses to the ICF, pushing K towards
Rina8888 [55]

Answer:

Hyperkalemia

Explanation:

The condition of acidosis can also cause Hyperkalemia because the higher H concentration diffuses to the ICF, pushing K towards the ECF.

4 0
2 years ago
Antacid tablets commonly contain calcium carbonate and/or magnesium hydroxide. draw the lewis structure for calcium carbonate an
Katyanochek1 [597]
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7 0
3 years ago
Sugar crystals aren't very big when they stop growing. how could you make bigger sugar crystals?
hram777 [196]
DONT GIVE THEM WATER OR HEAT

7 0
3 years ago
Suppose 6.63g of zinc bromide is dissolved in 100.mL of a 0.60 M aqueous solution of potassium carbonate. Calculate the final mo
Alenkasestr [34]

Answer:

[Zn²⁺] = 4.78x10⁻¹⁰M

Explanation:

Based on the reaction:

ZnBr₂(aq) + K₂CO₃(aq) → ZnCO₃(s) + 2KBr(aq)

The zinc added produce the insoluble ZnCO₃ with Ksp = 1.46x10⁻¹⁰:

1.46x10⁻¹⁰ = [Zn²⁺] [CO₃²⁻]

We can find the moles of ZnBr₂ added = Moles of Zn²⁺ and moles of K₂CO₃ = Moles of CO₃²⁻ to find the moles of CO₃²⁻ that remains in solution, thus:

<em>Moles ZnB₂ (Molar mass: 225.2g/mol) = Moles Zn²⁺:</em>

6.63g ZnBr₂ * (1mol / 225.2g) = 0.02944moles Zn²⁺

<em>Moles K₂CO₃ = Moles CO₃²⁻:</em>

0.100L * (0.60mol/L) = 0.060 moles CO₃²⁻

Moles CO₃²⁻ in excess: 0.0600moles CO₃²⁻ - 0.02944moles =

0.03056moles CO₃²⁻ / 0.100L = 0.3056M = [CO₃²⁻]

Replacing in Ksp expression:

1.46x10⁻¹⁰ = [Zn²⁺] [0.3056M]

<h3>[Zn²⁺] = 4.78x10⁻¹⁰M</h3>

4 0
3 years ago
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