C.
centi- is essentially 10^2 of one meter.
If you had 100m, multiplying 100 by 10^2 (or 100) would give you 10000 cm.
The formula of Iron(III) oxide is Fe2O3
In order to calculate the mass of iron in a given sample of iron(III) oxide, we must first know the mass percentage of iron in iron(III) oxide. This is calculated by:
[mass of iron in one mole of iron(III) oxide/ mass of one mole of iron(III) oxide] * 100
= [(moles of iron * Mr of iron) / (moles of Iron * Mr of Iron + moles of Oxygen * Mr of Oxygen)] * 100
= [(2 * 56) / (2 * 56 + 3 * 16)] * 100
= (112 / 160) * 100
= 70%
Thus, in a 100g sample, the weight of iron will be:
100 * 70%
= 70 grams
Since one atmosphere is 29.9213 inches of mercury, we can simply find this by taking 29.9213 and multiplying that by 1.24. You end up with 37.102412 inches of mercury. I hope this helps you out, and good luck on the rest of your homework.
Answer : It takes time to produce 3 g of aluminium is, 165 seconds.
Explanation :
As we are given that the mass of aluminium is, 3 grams. Now we have to calculate the total mass of aluminum.
Total mass of aluminum = 3g × 24 = 72 g
Now we have to calculate the moles of aluminum.
Molar mass of Al = 27 g/mol
As, 1 mole of Al has 3 Faradays
So, 2.67 mole of Al has = 
Faradays
and,
Charge = 
Current = 
Now we have to calculate the time.
Hence, it takes time to produce 3 g of aluminium is, 165 seconds.
.....i don't understand the question sorry
