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Eddi Din [679]
2 years ago
11

in triangle ABC, m ZA=55, m Z B=30, and a= 8. which equation should you solve to find b? PLEASE HELP IM BEING TIMED!!!!

Mathematics
1 answer:
Nina [5.8K]2 years ago
6 0

Answer:

Answer choice B

Step-by-step explanation:

Law of sines

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Regular and hexagon

Step-by-step explanation:

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3 years ago
Part a: what is the initial value of the function? what does it mean in the context of the situation?
ser-zykov [4K]

Answer:

Initial value = 10, slope = 4

Step-by-step explanation:

Initial value is the point where x takes its lowest value. In this case it is x = 0 and y = 10. Rate of change is the slope at a given point. Because this is a first order equation graph the slope is always the same. And in this case it is 4 as for every 1 unit of x the y goes 4.

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3 years ago
Which equation best represents the line of best fit for the scatterplot?
Masja [62]

Answer:

The line of best fit would be the line in between all the points in the scatter plot that is the closest to having an equal amount of dots on each side.

If there isn't one with the exact number, pick the one that is the <em>very closest</em>.

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3 years ago
Select the correct answer. 3 Twenty-seven minus 2 of a number (X) is not more than 36. What is the number? N O A. x &gt; 42 OB.
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the answer should be A.

Step-by-step explanation:

- College brother

3 0
3 years ago
From a window 20 feet above the ground, the angle of elevation to the top of a building across
Nikitich [7]

Answer: The answer is 381.85 feet.

Step-by-step explanation:  Given that a window is 20 feet above the ground. From there, the angle of elevation to the top of a building across  the street is 78°, and the angle of depression to the base of the same building is 15°. We are to calculate the height of the building across the street.

This situation is framed very nicely in the attached figure, where

BG = 20 feet, ∠AWB = 78°, ∠WAB = WBG = 15° and AH = height of the bulding across the street = ?

From the right-angled triangle WGB, we have

\dfrac{WG}{WB}=\tan 15^\circ\\\\\\\Rightarrow \dfrac{20}{b}=\tan 15^\circ\\\\\\\Rightarrow b=\dfrac{20}{\tan 15^\circ},

and from the right-angled triangle WAB, we have'

\dfrac{AB}{WB}=\tan 78^\circ\\\\\\\Rightarrow \dfrac{h}{b}=\tan 15^\circ\\\\\\\Rightarrow h=\tan 78^\circ\times\dfrac{20}{\tan 15^\circ}\\\\\\\Rightarrow h=361.85.

Therefore, AH = AB + BH = h + GB = 361.85+20 = 381.85 feet.

Thus, the height of the building across the street is 381.85 feet.

8 0
3 years ago
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