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3 years ago

what is an equation in point-slope form of the line that passes through the points (4, 5) and (-3, -1)???

Mathematics

1 answer:

Vikentia [17]3 years ago

7 0

Are you mrs woods class or sumn

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Write the translation

tatiyna

Translate 5 units to the right, and 2 units down

8 0

4 years ago

144 flowers in a vase the ratio of yellow to pink flowers is 5 to 6 how many yellow flowers are in the vase

azamat

$\frac{5}{11} \times 144 \: is \: the \: amount \: of \: yellow \: flowers \\ \\ \frac{5}{11} \times 144 = 65.45 = 65$
therfore there is 65 yellow flowers

4 0

3 years ago

point X is located at (2,-6), and point Z is located at (0,5). find the value for the point Y that is located 1/5 the distance f

HACTEHA [7]

Let point is(x,y)
x=(2-0)/5=2/5
y=(-6-5)/5=-11/5
(2/5,-11/5)

8 0

3 years ago

The mean salary of 5 employees is $33700. The median is $34600. The mode is $35600. If the median paid employee gets a $3500 rai

fgiga [73]

Step-by-step explanation:

Given:

Mean = 33700

Median = 34600

Mode = 35600

The mean is the average, the median is the middle number, and the mode is the most common number.

First, we need to find the new mean (average) if one of the employees gets a 3500 raise. The average is the total salary divided by number of employees:

(5 × 33700 + 3500) / 5 = 34400

The mode is the most common number in a set. Since there are only five employees, and the mode is different than the median, then the two highest earners must have the same salary. The salaries from smallest to largest is therefore:

?, ?, 34600, 35600, 35600

When the median gets the 3500 raise, the set becomes:

?, ?, 35600, 35600, 38100

So the new median is 35600.

The most common number is still 35600. So the mode hasn't changed: 35600.

4 0

3 years ago

Determine the amplitude (A), period (P), and phase shift (PS) of the function f(x)= 3sin(x-4)+9

Tpy6a [65]

ANSWER

D.
$A=3,P=2\pi,PS=(4,9)$

EXPLANATION

The given function is

$f(x) = 3 \sin(x - 4) + 9$

Comparing to the general form of a trigonometric sine function,

$f(x) = A \sin(Bx-C)+D$

$A=3$
The amplitude is absolute value of A

$|A| = |3| = 3$

$B=1$

The period is given by

$p = \frac{2\pi}{ B}$

$p = \frac{2\pi}{ 1} = 2\pi$

$C=4$

is a shift to the right of 4 units.

and

$D=9$

is an upward shift of 9 units

Therefore the phase shift is (4,9).

The correct answer is D

6 0

3 years ago