The magnitude is 53N and the direction is 3 degrees. I hope this helps!
Answer:
Explanation:
Given
initial speed ![=v_i](https://tex.z-dn.net/?f=%3Dv_i)
coefficient of kinetic friction![=\mu](https://tex.z-dn.net/?f=%3D%5Cmu%20)
It moves a distance d after that it comes to rest
acceleration offered by table top![=\mu g](https://tex.z-dn.net/?f=%3D%5Cmu%20g)
![v^2-u^2=2as](https://tex.z-dn.net/?f=v%5E2-u%5E2%3D2as)
![0-(v_i)^2=2(-\mu g)d](https://tex.z-dn.net/?f=0-%28v_i%29%5E2%3D2%28-%5Cmu%20g%29d)
![v_i=\sqrt{2(\mu g)d}](https://tex.z-dn.net/?f=v_i%3D%5Csqrt%7B2%28%5Cmu%20g%29d%7D)
Fatigue is the number one cause of accidents.
Explanation:
Given:
v₀ = 0 m/s
a = 9.8 m/s²
a) Find v when t = 5.00 s.
v = at + v₀
v = (9.8 m/s²) (5.00 s) + 0 m/s
v = 49.0 m/s
b) Find Δx when v = 32.0 m/s.
v² = v₀² + 2aΔx
(32.0 m/s)² = (0 m/s)² + 2 (9.8 m/s²) Δx
Δx = 52.2 m