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choli [55]
3 years ago
14

How much energy is imparted to an electron as it flows through a 6 V battery from the positive to the negative terminal? Express

your answer in attojoules.
Physics
1 answer:
Hatshy [7]3 years ago
8 0
The potential difference does work on the electron. The work is given by:
W = Vq
W = work, V = potential difference, q = electron charge

Given values:
V = 6V, q = 1.6x10^-19C

Plug in and solve for W:
W = 6(1.6x10^-19)
W = 0.96aJ
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3 years ago
A marathon runner runs at a steady 15 km/hr. When the runner is 7.5 km from the finish, a bird begins flying from the runner to
Whitepunk [10]

Answer:

The value is D =  15 \  km

Explanation:

From the question we are told that

   The  speed of the marathon runner is  v  =  15 \  km /hr

   The distance from the distance from the finish is  d =  7.5 \  km

   The  speed of the bird is  v_b  =  30 \ km / hr

  Generally the time taken for the runner to reach the finish is mathematically represented as

       t =  \frac{d}{v}

       t =  \frac{7.5}{15}

        t =  \frac{1}{2}

So the distance covered by the bird is  

      D =  v_b  *  t

      D =  30  *  \frac{1}{2}

         D =  15 \  km

6 0
3 years ago
The rate constant of a reaction is 7.8 × 10−3 s−1 at 25°C, and the activation energy is 33.6 kJ/mol. What is k at 75°C? Enter yo
Alexus [3.1K]

Answer:

k_2 = 7.815 * 10^-3 s^-1

Explanation:

Given:

- rate constant of reaction k_1 = 7.8 * 10^-3 s^-1    @  T_1 = 25 C

- rate constant of reaction k_2 = ?    @  T_2 = 75 C

- The activation energy E_a = 33.6 KJ/mol

- Gas constant R = 8.314472 KJ / mol . K

Find:

- rate of reaction k_2 @ T_2 = 75 C

Solution:

- we will use a combined form of Arrhenius equations that relates rate constants k as function of E_a and temperatures as follows:

                              k_2 = k_1 * e ^ [(E_a / R) * ( 1 / T_1 - 1 / T_2 )

- Evaluate             k_2 = 7.8 * 10^-3* e^[(33.6 / 8.314472)*(1/298 -1/348)

- Hence,                k_2 = 7.815 * 10^-3 s^-1

4 0
4 years ago
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