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choli [55]
3 years ago
14

How much energy is imparted to an electron as it flows through a 6 V battery from the positive to the negative terminal? Express

your answer in attojoules.
Physics
1 answer:
Hatshy [7]3 years ago
8 0
The potential difference does work on the electron. The work is given by:
W = Vq
W = work, V = potential difference, q = electron charge

Given values:
V = 6V, q = 1.6x10^-19C

Plug in and solve for W:
W = 6(1.6x10^-19)
W = 0.96aJ
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Seismic activityis/are) one type of tectonic event captured in geologic maps.

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Use the specific heat values to answer the
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6 0
3 years ago
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the resultant vector of two particular displacement vectors does not equal the sum of the magnitude of the individual vectors.de
nekit [7.7K]

If the  magnitude of the resultant of two vectors doesn't equal the sum
of their individual magnitudes, then they can have ANY directions, EXCEPT
only that they can't both be in the SAME direction.

3 0
4 years ago
an 80.0 kg astronaut carrying a 15.0 kg tool kit is drifting away from the space station at a speed of 1.25 m/s. a) if she throw
jasenka [17]

The final speed of the astronaut at the space station is <u>0.36 m/s</u> and the direction will be <u>opposite</u> to the direction of the tool kit thrown.

The mass of the astronaut = 80 kg

The mass of the tool kit = 15 kg

The speed of the space station = 1.25 m/s

The speed of the tool kit threw = 6 m/s

The final speed of the astronaut can be found using the conservation of momentum formula,

           \displaystyle m_{1}v_{f1} + m_{2}v_{f2} = m_{1}v_{i1} + m_{2}v_{i2}

where m₁ is the mass of the astronaut

           m₂ is the mass of the tool kit

           \displaystyle v_{i1} and \displaystyle v_{i2} is the speed of the space station

           \displaystyle v_{f1} is the speed of the astronaut after throwing the toolkit

Let us substitute the known values in the above equation, we get

              (80 x \displaystyle v_{f1}) + (15 x 6) = (80 x 1.25) + (15 x 1.25)

                     (80 x \displaystyle v_{f1}) + 90 = 100 + 18.75

                              80 x \displaystyle v_{f1}   = 118.75 - 90

                                80 x \displaystyle v_{f1} = 28.75

                                        \displaystyle v_{f1} = 28.75 / 80

                                              = 0.36 m/s

Therefore, the final speed of the astronaut is <u>0.36 m/s</u>

By newton's third law, for every action, there will be an equal and opposite reaction. Thus, the direction of the astronaut's direction will be against the direction of the tool kit thrown.

Learn more about the conservation of momentum in

brainly.com/question/2456421

#SPJ4

5 0
1 year ago
A space probe is launched from Earth headed for deep space. At a distance of 10,000 miles from Earth's center, the gravitational
Pani-rosa [81]
Grav Force = GMm/r squared. M is earth's mass. m is the probe. r is distance to centre of earth.Given that 600 = GMm/(10,000^2).GMm = 600x(10,000^2) for 10, 000 milesGMm = ? x (20,000^2) for 20, 000 milestherefore600x(10,000^2)=? x (20,000^2)therefore [600x(10,000^2)]/(20,000^2)=? [600x(1x1)]/(2x2)=? [600/4]=? ?=150lb.Same procedure for b and c.Please ask if you want further help.
3 0
3 years ago
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