Answer:
Explanation:
Hello there!
In this case, according to the given information, it turns out possible for us to find the molecular formula of the given compound by firstly calculating both moles and grams of carbon in carbon dioxide and hydrogen in water, as the only sources of these elements derived from the compound x due to its combustion:
Now, since the addition of carbon and hydrogen is about 6.50 grams, we infer the compound has no oxygen, that is why we now set the mole ratios in the empirical formula for both C and H as shown below:
Yet it cannot be decimal, that is why we multiply by 4 to get the correct whole-numbered empirical formula:
Whose molar mass is 64.09 g/mol, which makes the ratio of molar masses:
Therefore, the molecular formula is twice the empirical one:
Regards!
Answer:
its 0.163 g
Explanation:
From the total pressure and the vapour pressure of water we can calculate the partial pressure of O2
PO 2 =P t −P H 2 O
= 760 − 22.4
= 737.6 mmHg
From the ideal gas equation we write.
W= RT/PVM = (0.0821Latm/Kmol)(273+24)K(0.974atm)(0.128L)(32.0g/mol/) =0.163g
The molarity of a 27%(v/v) aqueous ethanol solution is 4.63 M
calculation
convert 27%(v/v) to fraction = 27ml/100 ml
use density to convert 27ml to grams = 27 ml x0.79 g/ml = 21.33 g
find the number of moles of C2H6O
moles = mass/molar mass of C2H6O(46.07 g/mol)
moles is therefore = 21.33 g /46.07 g/mol =0.463 moles
find the molarity = moles /volume in liters
volume in liter = 100 ml/1000 = 0.1 L
molarity is therefore = 0.463 mole/0.1 L = 4.63 M
Answer: V2= 15.0403226 Liters
Explanation:
Use V1/T1=V2/T2
Make sure you change the degrees Celsius to Kelvin. (Kelvin = degrees Celsius +273)
10.0L / 248 K = V2/ 373 K
Cross multiply V1 and T2 and divide by T1
(10.0 L)( 373K)/ 248 K = V2
V2= 15.0403226 Liters (Kelvin cancels out)
The spontaneous disintegration of a nucleus into a slightly lighter and more <u>radioactive </u>nucleus is accompanied by the emission of particles, electromagnetic radiation, or both.
Radioactivity is the phenomenon of the spontaneous disintegration of unstable atomic nuclei into atomic nuclei to shape greater energetically strong atomic nuclei.
Radioactive decay is a tremendously exoergic, statistically random, first-order system that occurs with a small amount of mass being converted to strength.
Spontaneous disintegration of a radionuclide with the emission of lively particles or radiation, consisting of alpha or beta debris or gamma rays.
Learn more about Radioactive decay here: brainly.com/question/4149380
#SPJ4
