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jolli1 [7]
3 years ago
12

The wavelength propagates to 15 m with a frequency of 0.3 HZ What is the speed of this wave?

Chemistry
1 answer:
ololo11 [35]3 years ago
8 0

Answer:

c=50\frac{m}{s}

Explanation:

Hello!

In this case, given the relationship between velocity, wavelength and frequency:

c=\lambda *f

By plugging in the given wavelength and frequency, we obtain the following speed:

c=15m*0.3\frac{1}{s}\\\\c=50\frac{m}{s}

Best regards!

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Arun and Marcus are asked to compare the solubility of two salts in water at room temperature. The two salts are labelled X and
oksian1 [2.3K]

Answer:

1) Salts X and Y

2) The solubility of the salts

3) a) The solvent

b) The solvent temperature

Explanation:

1) The independent variable is the variable that is suspected to be the cause of the subject of the investigation

The given investigation is meant to investigate the solubility of different salts

Therefore, the solubility is expected to be dependent on the type of salt, and the independent variable is the type of salt, X or Y

2) The dependent variable is the effect meant to be observed in the investigation, which is the solubility of the salt in water at room temperature

3) The control variables are the variables which are held constant during the investigation, including;

a) The solvent used if the investigation; water

b) The temperature of the solvent; Room temperature

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3 years ago
What volume, in milliliters, of a 0.997 M KOH solution is needed to neutralize 30.0 mL of 0.0400 M HCl?
deff fn [24]

Answer:

1.2 mL

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated:

HCl + KOH —> KCl + H₂O

From the balanced equation,

Mole ratio of the acid, HCl (nₐ) = 1

Mole ratio of base, KOH (n₆) = 1

Finally, we shall determine the volume of the base, KOH needed to neutralize the acid, HCl as follow:

Molarity of base, KOH (M₆) = 0.997 M

Volume of acid, HCl (Vₐ) = 30 mL

Molarity of acid, HCl (Mₐ) = 0.0400 M

Volume of base, KOH (V₆) =?

MₐVₐ / M₆V₆ = nₐ/n₆

0.04 × 30 / 0.997 × V₆ = 1/1

1.2 / 0.997 × V₆ = 1

Cross multiply

0.997 × V₆ = 1.2

Divide both side by 0.997

V₆ = 1.2 / 0.997

V₆ = 1.2 mL

Thus, the volume of the base, KOH needed to neutralize the acid is 1.2 mL.

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3 years ago
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Answer:

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8 0
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Complete the following table for the three key subatomic particles.
ASHA 777 [7]

Answer:

This question is incomplete without the table

Explanation:

The missing table is attached to this answer.

There are three subatomic particles found in an atom; protons, neutrons and electrons. The properties of the subatomic particles will be classified under the following subheadings (which are the empty columns/boxes in the attachment)

SYMBOL

The symbol of proton is "p⁺", the symbol of neutron is "n⁰" and the symbol of electron is "e⁻".

CHARGE

Looking at the symbol of the subatomic particles, one can guess the charge of each of the particles from the superscript.

Protons are positively charged, electrons are negatively charged while neutrons have no charge/electrically neutral.

The relative charge of proton is +1 while it's absolute charge is +1.60218 × 10⁻¹⁹

The charge of a proton was first determined by Ernest Rutherford using the gold-foil experiment

The relative charge of electron is -1 while it's absolute charge is -1.60218 × 10⁻¹⁹

The charge of an electron was first determined by R. Milikan using the oil-drop experiment

The relative charge and absolute charge of neutron is 0

The charge of a neutron was first determined by (or credited to) James Chadwick.

MASS

The relative mass (amu) of proton is 1.00727 while that of neutron is 1.00866. The relative mass (amu) of an electron is 0.00054858 while it's absolute mass (g) is 9.10939 × 10⁻²⁴.

The mass of an electron was first measured by J. J. Thomson.

The mass of a proton was first measured by (or credited to) Ernest Rutherford.

The mass of a neutron was first measured by James Chadwick.

LOCATION

The protons and neutrons <u>are located inside the nucleus</u> which is found in the centre of an atom while the electron(s)<u> is/are found outside the nucleus but within the atom</u>.

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