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ella [17]
3 years ago
14

Describe what Rutherford would have seen in his gold foil experiment if J.J Thompson's Plum Pudding model was completly accurate

Chemistry
1 answer:
nata0808 [166]3 years ago
6 0
Answer is: Rutherford demonstrate that <span>J.J Thompson's Plum Pudding model was not accurate.

</span><span>Rutherford theorized that atoms have their charge concentrated in a very small nucleus.
</span>This was famous Rutherford's Gold Foil Experiment: he bombarded thin foil of gold with positive alpha particles (helium atom particles, consist of two protons and two neutrons).
Rutherford observed the deflection of alpha particles on the photographic film and notice that most of alpha particles passed straight through foil.
That is different from Plum Pudding model<span>, because it shows that most of the atom is empty space.</span><span>

</span>
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3 years ago
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irina [24]

Answer:

0.0073 g

Explanation:

Considering:

Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}

Or,

Moles =Molarity \times {Volume\ of\ the\ solution}

Given :

For HCl :

Molarity = 0.010 M

Volume = 25 mL

The conversion of mL to L is shown below:

1 mL = 10⁻³ L

Thus, volume = 25×10⁻³ L

Thus, moles of HCl :

Moles=0.010 \times {25\times 10^{-3}}\ moles

Moles of HCl  = 0.00025 moles

Considering the reaction shown below as:-

2HCl+Mg(OH)_2\rightarrow MgCl_2+2H_2O

2 moles of HCl reacts with 1 mole of Mg(OH)_2

So,

1 moles of HCl reacts with 1/2 mole of Mg(OH)_2

Also,

0.00025 moles of HCl reacts with \frac{1}{2}\times 0.00025 mole of Mg(OH)_2

Mole of Mg(OH)_2 = 0.000125 moles

Molar mass of Mg(OH)_2 = 58.3197 g/mol

Mass = Moles*Molar mass = 0.000125\times 58.3197\ g = 0.0073 g

5 0
3 years ago
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3 years ago
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