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viva [34]
3 years ago
13

A runner has a speed of 5m/s and a mass of 130 kg what is his kinetic energy?

Physics
2 answers:
emmainna [20.7K]3 years ago
6 0

Answer:

1625

Explanation:

apx

arlik [135]3 years ago
4 0
M= 130 kg

v= 5 m/s

kinetik energy = ½• m•v²


= ½ • 130• 5²
= ½•130•25
= ½•3250
= 1625.
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Someone help please.....
Westkost [7]

Answer:

0.0928km/min (4dp)

Explanation:

To find the jogger's speed in km per minute, we just need to divide the number of km jogged by the time in minutes it took to jog that distance. This will give us the distance they jogged every minute which is their speed.

4km in 32 minutes:

4/32 = 0.125km/min

2km in 22 minutes:

2/22 = 0.091 (3dp)km/min

1km in 16 minutes:

0.0625km/min

Now to find the average speed of these 3 speeds, we just add them all together and divide by how many values there are (3 values).

Average (mean)  = \frac{0.125+0.091+0.0625}{3}

Average = 0.2785/3

Average speed of jogger = 0.0928 (4dp) km/min

Hope this helped!

8 0
3 years ago
Why does air blow out of your lungs when you exhale
Levart [38]
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8 0
3 years ago
Read 2 more answers
A car traveling 36 mi/h accelerates uniformly
iren2701 [21]

First convert from mi/h to ft/s. There are 5280 ft to 1 mi, and 3600 s to 1 h, so

36 mi/h = (36 mi/h) * (5280 ft/mi) * (1/3600 h/s) = 52.8 ft/s

Let <em>a</em> be the acceleration of the car. The car's speed at time <em>t</em> is

<em>v</em> = 52.8 ft/s + <em>a</em> <em>t</em>

so that after 5.4 s, it attains a speed of

<em>v</em> = 52.8 ft/s + (5.4 s) <em>a</em>

Recall that

<em>v</em>² - <em>u</em>² = 2 <em>a</em> ∆<em>x</em>

where <em>u</em> is the car's initial velocity and ∆<em>x</em> is the distance it's traveled.

We have

(52.8 ft/s + (5.4 s) <em>a</em>)² - (52.8 ft/s)² = 2 <em>a</em> (595 ft)

Omitting units, this equation reduces to

(52.8 + 5.4 <em>a</em>)² - 52.8² = 1190 <em>a</em>

==>  29.16 <em>a</em>² - 619.76 <em>a</em> = 0

==>  29.16 <em>a</em> - 619.76 = 0

==>  29.16 <em>a</em> = 619.76

==>  <em>a</em> ≈ 21.25 ft/s²

7 0
3 years ago
How much force is required to accelerate 3 kg at 3 m/sec^2
bogdanovich [222]

Answer:

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Explanation:

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Sum of number of protons and neutrons in the nucleus
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That's the "Atomic Mass" of the atom.

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