A runner has a speed of 5m/s and a mass of 130 kg what is his kinetic energy?
2 answers:
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Answer:
Not possible
Explanation:
= longitudinal modulus of elasticity = 35 Gpa
= transverse modulus of elasticity = 5.17 Gpa
= Epoxy modulus of elasticity = 3.4 Gpa
= Volume fraction of fibre (longitudinal)
= Volume fraction of fibre (transvers)
= Modulus of elasticity of aramid fibers = 131 Gpa
Longitudinal modulus of elasticity is given by
Transverse modulus of elasticity is given by
Hence, it is not possible to produce a continuous and oriented aramid fiber.
The average speed of the car for the entire trip can be calculate by using:
where S is the total distance covered by the car, and t is the total time taken.
The total distance travelled by the car is:
while the total time taken is:
so, the average speed of the car is:
so, the correct answer is (3) 85 km/h.
Answer:
346.70015 m/s
Explanation:
In the x axis speed is
In the y axis
The resultant velocity is given by
The magnitude of the overall velocity of the hamper at the instant it strikes the surface of the ocean is 346.70015 m/s
Answer:
B = 0.8 T
Explanation:
It is given that,
Radius of circular loop, r = 0.75 m
Current in the loop, I = 3 A
The loop may be rotated about an axis that passes through the center and lies in the plane of the loop.
When the orientation of the normal to the loop with respect to the direction of the magnetic field is 25°, the torque on the coil is 1.8 Nm.
We need to find the magnitude of the uniform magnetic field exerting this torque on the loop. Torque acting on the loop is given by :
B is magnetic field
So, the magnitude of the uniform magnetic field exerting this torque on the loop is 0.8 T.