Let's solve your equation step-by-step.<span><span><span>2x</span>+<span>3<span>(<span>x−4</span>)</span></span></span>=<span>x−20</span></span>Step 1: Simplify both sides of the equation.<span><span><span>2x</span>+<span>3<span>(<span>x−4</span>)</span></span></span>=<span>x−20</span></span><span>Simplify: (Show steps)</span><span><span><span>5x</span>−12</span>=<span>x−20</span></span>Step 2: Subtract x from both sides.<span><span><span><span>5x</span>−12</span>−x</span>=<span><span>x−20</span>−x</span></span><span><span><span>4x</span>−12</span>=<span>−20</span></span>Step 3: Add 12 to both sides.<span><span><span><span>4x</span>−12</span>+12</span>=<span><span>−20</span>+12</span></span><span><span>4x</span>=<span>−8</span></span>Step 4: Divide both sides by 4.<span><span><span>4x/</span>4</span>=<span><span>−8/</span>4</span></span><span>x=<span>−2</span></span>Answer: x=−2
Answer:
The given statement is true because the person they did their steps correctly
a) Locate a point C so that ABC is a right triangle with m ACB ∠ = ° 90 and the measure of one of the acute angles in the triangle is 45° .
b) Locate a point D so that ABD is a right triangle with m ADB ∠ = ° 90 and
the measure of one of the acute angles in the triangle is30° .
c) Locate a point E so that ABE is a right triangle with m AEB ∠ = ° 90 and
the measure of one of the acute angles in the triangle is15° .
d) Find the distance between point C and the midpoint of segment AB .
Repeat with points D and E.
e) Suppose F is a point on the graph so that ABF is a right triangle
withm AFB ∠ =° 90 . Make a conjecture about the point F.
3x(d+7) < 5d-13 (I think it is
4.7 because if you plug it in- (2,1) and (6,6) it is 4.7 units
$3,456 will be given to the band.
Simply multiplying 57,600 and 6% which is 0.06, you get 3,456.
