Which is the exact equivalent of 7/12<br> A.) 0.583<br> B.) 1.714

Addison worked 11 more hours this week than last week. In total, she worked 65 hours this week and last week. Using the equation

Anestetic [448]

Answer:

27 hours

Step-by-step explanation:

Just do the reverse. 65-11 = 54. 54 / 2 = 27.

5 0

2 years ago

Can someone plzzz help me with this math practice paper

weeeeeb [17]

Answer:

45 degrees for 8

135 degrees for 9

48 for 10

Yes a square is a rectangle

Next ones.

Sut = 21 becuase x=5

7

Step-by-step explanation:

Last one:

x^2 + 8 = 3x + 36

- 8 - 8

x^2 = 3x + 28

-3x -3x

x^2 - 3x = 28

(x · x) - 3x = 28.

This was were a little guess work was used,

I found that any number lower than 7 is less than 28 when pluged into x and any above is higher.

Hence x = 7

So

x^2 + 8 = 7^2 + 8

7 x 7 = 49. 49 + 8 = 57.

and

3x+36 = 7 x 3 + 36

7x3 = 21. 21 + 36 = 57.

Both lines are equal so x is indeed 7.

The RSTU rectangle

3x+6 = 5x-4

+4 +4

3x+10 = 5x

-3x -3x

10 = 2x

10/2 = 5

5 = x or x = 5

plug it in now

3 x 5 = 15. 15 + 6 = 21

and

5 x 5 = 25. 25 - 4 = 21

so x = 5

8-10

QRS = 45 degrees because bisects the square with a diagonal line from corner to corner

PTQ is a 135 degrees because it is wider than a 90 degrees angle and meets both upper corner from the middle of the square making it 135 degrees.

SQ = 48 because RT = 24 and RT is half the length of SQ meaning its length would be 48

Or

SQ= 24 degrees because RT = 24 and if RT was to continue on the line it is on it will reach the length of SQ.

3 0

3 years ago

Sara is saving her summer earnings for a $500 school trip in the fall. She has $200 in her savings account at the beginning of J

Vilka [71]

Answer:she will need around 9 weeks and she will have enuogh

Step-by-step explanation:

9

5 0

3 years ago

The CPA Practice Advisor reports that the mean preparation fee for 2017 federal income tax returns was $273. Use this price as t

skad [1K]

Answer:

a) 0.6212 = 62.12% probability that the mean price for a sample of 30 federal income tax returns is within $16 of the population mean.

b) 0.7416 = 74.16% probability that the mean price for a sample of 50 federal income tax returns is within $16 of the population mean.

c) 0.8804 = 88.04% probability that the mean price for a sample of 100 federal income tax returns is within $16 of the population mean.

d) None of them ensure, that one which comes closer is a sample size of 100 in option c), to guarantee, we need to keep increasing the sample size.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

The CPA Practice Advisor reports that the mean preparation fee for 2017 federal income tax returns was $273. Use this price as the population mean and assume the population standard deviation of preparation fees is $100.

This means that $\mu = 273, \sigma = 100$

A) What is the probability that the mean price for a sample of 30 federal income tax returns is within $16 of the population mean?

Sample of 30 means that $n = 30, s = \frac{100}{\sqrt{30}}$

The probability is the p-value of Z when X = 273 + 16 = 289 subtracted by the p-value of Z when X = 273 - 16 = 257. So

X = 289

$Z = \frac{X - \mu}{\sigma}$

By the Central Limit Theorem

$Z = \frac{X - \mu}{s}$

$Z = \frac{289 - 273}{\frac{100}{\sqrt{30}}}$

$Z = 0.88$

$Z = 0.88$ has a p-value of 0.8106

X = 257

$Z = \frac{X - \mu}{s}$

$Z = \frac{257 - 273}{\frac{100}{\sqrt{30}}}$

$Z = -0.88$

$Z = -0.88$ has a p-value of 0.1894

0.8106 - 0.1894 = 0.6212

0.6212 = 62.12% probability that the mean price for a sample of 30 federal income tax returns is within $16 of the population mean.

B) What is the probability that the mean price for a sample of 50 federal income tax returns is within $16 of the population mean?

Sample of 30 means that $n = 50, s = \frac{100}{\sqrt{50}}$

X = 289

$Z = \frac{X - \mu}{\sigma}$

By the Central Limit Theorem

$Z = \frac{X - \mu}{s}$

$Z = \frac{289 - 273}{\frac{100}{\sqrt{50}}}$

$Z = 1.13$

$Z = 1.13$ has a p-value of 0.8708

X = 257

$Z = \frac{X - \mu}{s}$

$Z = \frac{257 - 273}{\frac{100}{\sqrt{50}}}$

$Z = -1.13$

$Z = -1.13$ has a p-value of 0.1292

0.8708 - 0.1292 = 0.7416

0.7416 = 74.16% probability that the mean price for a sample of 50 federal income tax returns is within $16 of the population mean.

C) What is the probability that the mean price for a sample of 100 federal income tax returns is within $16 of the population mean?

Sample of 30 means that $n = 100, s = \frac{100}{\sqrt{100}}$

X = 289

$Z = \frac{X - \mu}{\sigma}$

By the Central Limit Theorem

$Z = \frac{X - \mu}{s}$

$Z = \frac{289 - 273}{\frac{100}{\sqrt{100}}}$

$Z = 1.6$

$Z = 1.6$ has a p-value of 0.9452

X = 257

$Z = \frac{X - \mu}{s}$

$Z = \frac{257 - 273}{\frac{100}{\sqrt{100}}}$

$Z = -1.6$

$Z = -1.6$ has a p-value of 0.0648

0.9452 - 0.0648 =

0.8804 = 88.04% probability that the mean price for a sample of 100 federal income tax returns is within $16 of the population mean.

D) Which, if any of the sample sizes in part (a), (b), and (c) would you recommend to ensure at least a .95 probability that the same mean is withing $16 of the population mean?

None of them ensure, that one which comes closer is a sample size of 100 in option c), to guarantee, we need to keep increasing the sample size.

6 0

2 years ago

True or False: (x + 3)2 = x2 + 9

malfutka [58]

Answer:

false

Step-by-step explanation:

3 0

3 years ago

Which is the exact equivalent of 7/12 A.) 0.583 B.) 1.714