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Svet_ta [14]
2 years ago
14

According to Newton's third law, which describes what happens when a 4.5 kg pumpkin is launched from a catapult with a force of

47.5 Newtons?
A.
The pumpkin exerts a force of 43 N back against the catapult.

B.
The pumpkin exerts a force of 52 N back against the catapult.

C.
The pumpkin exerts a force of 4.5 N back against the catapult.

D.
The pumpkin exerts a force of 47.5 N back against the catapult.
Physics
1 answer:
max2010maxim [7]2 years ago
6 0
3. Law: Every action has a reaction equal in magnitude and opposite in direction.
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Answer:

10 ohms... are you clear with it

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deals with the concepts that are important in this problem. A grasshopper makes four jumps. The displacement vectors are (1) 31.
Troyanec [42]

(a) 46.6 cm

To calculate the total displacement, we need to resolve each vector along the x- and y- direction.

In the following, we take:

- East as positive x-direction, West as negative x-direction

- North as positive y-direction, South as negative y-direction

Vector A:

A_x = -31.0 cm\\A_y = 0

Vector B:

B_x = -(32.0 cm) cos 34.0^{\circ}=-25.6 cm\\B_y = -(32.0 cm) sin 34.0^{\circ} = -17.9 cm

Vector C:

C_x = (16.0 cm)cos 57.0^{\circ} =8.7 cm\\C_y = -(16.0 cm)sin 57.0^{\circ} =-13.4 cm

Vector D:

D_x = (16.0 cm) cos 75.0^{\circ} =4.1 cm\\D_y = (16.0 cm) sin 75.0^{\circ} =15.5 cm

So the components of the total displacement are:

R_x = -31.0 cm - 25.6 cm +8.7 cm +4.1 cm =-43.8 cm\\R_y = 0-17.9 cm -13.4 cm +15.5 cm =-15.8 cm

So the magnitude of the total displacement is:

R=\sqrt{R_x^2 + R_y^2}=\sqrt{(-43.8 cm)^2+(-15.8 cm)^2}=46.6 cm

(b) 19.8 degrees south of west

First of all, let's notice that:

- both components x and y of the total displacement are negative --> this means that the direction of the displacement is south of west

This means that the angle will be given by

\theta = tan^{-1} (\frac{R_y}{R_x})

where we have

R_x = -43.8 cm\\R_y = -15.8 cm

Substituting, we find

\theta = tan^{-1} (\frac{-15.8 cm}{43.8 cm})=19.8^{\circ}

and this angle is south of west.

7 0
3 years ago
Election x falls from engery level a to engery level b and releases blue light. Elsctron y falls from energy level an to engery
pashok25 [27]

Answer

From A to B

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from the spectrum of visible light ,the production red light has the lowest energy difference as the wavelength is shorter and frequency lower

on the other hand, blue light is produced when the energy difference is higher.

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A transverse wave has an amplitude of 2.4m. What is the vertical distance, in meters, between the top of a Crest and the bottom
Alex17521 [72]

Answer:

4.8 m

Explanation:

A transverse wave is a wave in which the oscillation of the particles occur in a direction perpendicular to the direction of motion of the wave.

The amplitude of a transverse wave is the maximum displacement of the wave with respect to the equilibrium position.

The crest of a wave is the position of maximum displacement on the positive side, while the trough of a wave is the position of maximum displacement on the negative side.

This means that the amplitude of a wave is equal to the distance between a crest (or a trough) and the equilibrium position.

Therefore, we have:

d=2A

where:

d is the distance between the top of a crest and the bottom of a trough

A is the amplitude of the wave

Here we have:

A = 2.4 m

So, we find

d=2\cdot 2.4 = 4.8 m

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3 years ago
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