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Svet_ta [14]
3 years ago
14

According to Newton's third law, which describes what happens when a 4.5 kg pumpkin is launched from a catapult with a force of

47.5 Newtons?
A.
The pumpkin exerts a force of 43 N back against the catapult.

B.
The pumpkin exerts a force of 52 N back against the catapult.

C.
The pumpkin exerts a force of 4.5 N back against the catapult.

D.
The pumpkin exerts a force of 47.5 N back against the catapult.
Physics
1 answer:
max2010maxim [7]3 years ago
6 0
3. Law: Every action has a reaction equal in magnitude and opposite in direction.
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How many electrons does a neutral atom of sudium-25 have
horrorfan [7]

Answer:

Option A. 11

Explanation:

The atomic number of an element does not change.

Recall:

Atomic number = proton number

If the atom is neutral, then,

Proton number = electron number

Since the element is sodium, then, the atomic number of sodium–25 is 11.

Also, we were told to obtain the electrons of a neutral atom of sodium–25

Therefore,

Atomic number = proton number = 11

Since the atom is neutral,

Proton number = electron number = 11

8 0
3 years ago
A lawn roller is rolled across a lawn by a force of 107 N along the direction of the handle, which is 13.5 ◦ above the horizonta
-BARSIC- [3]

Answer:

22.02 m

Explanation:

given,

Force, F = 107 N

angle made with horizontal = 13.5◦

Power develop by the lawn roller = 69.4 W

time = 33 s

distance = ?

Force along horizontal= F cos θ

          = 107 cos 13.5°= 104 N

Power = \dfrac{work\ done}{time}

69.4 = \dfrac{W}{33}

W = 2290.2 J

Work done= Force x displacement

displacement= \dfrac{2290.2}{104}

                      = 22.02 m

6 0
3 years ago
What is the distance from the crest to the equilibrium of a wave called? A. amplitude B. period C. frequency D. phase
Goryan [66]

its the first one. A.

8 0
3 years ago
Read 2 more answers
Hiii please help i’ll give brainliest if you give a correct answer please thanks!
ryzh [129]

Answer:

i Guess 1 or 3

Explanation:

yea 1 or 3 or just  guess hard

7 0
3 years ago
A 500 N weight is hung at the middle of a rope attached to two buildings at the same level. If the breaks in the tension exceed
Lyrx [107]

Not sure what you mean by "breaks in the tension" but I suspect you mean the rope will come apart if the tension in the rope exceeds 1800 N.

In the free body diagram for the 500 N weight, we have a figure Y with the net force equations

• horizontal net force:

∑ F[hor] = T₁ cos(θ) - T₂ cos(θ) = 0

• vertical net force:

∑ F[ver] = T₁ sin(θ) + T₂ sin(θ) - 500 N = 0

From the first equation, it follows that T₁ = T₂, so I'll denote their magnitude by T alone. From the second equation, we have

2 T sin(θ) = 500 N

and if the maximum permissible tension is T = 1800 N, it follows that

sin(θ) = (500 N) / (3600 N)   ⇒   θ = arcsin(5/36) ≈ 7.9°

is the smallest angle the rope can make with the horizontal.

6 0
3 years ago
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