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Answer:
Explanation:
The rate of volume flow out of tank can be expressed as:
where,
dV/dt = Volume flow rate
A = Cross-sectional area of outlet = πd²/4
d = diameter of circular outlet
dL = Displacement covered by water
dt = time taken
but we know that:
Velocity = υ = displacement/time = dL/dt
Substituting the values of "dL/dt" and "A" in the equation, we get:
This is the expression for volume flow rate dV/dt, on terms pf v, d.
Answer:
A) 6.5 m/s²
Explanation:
Mass of the bucket, m = 3.0 kg
depth of the well, d = 10 m
tension on the rope, T = 9.8 N
The net downward force on the bucket is given as;
T = mg - ma
where;
a is downward acceleration of the bucket
9.8 = (3 x 9.8) - 3a
9.8 = 29.4 - 3a
3a = 29.4 - 9.8
3a = 19.6
a = 19.6 / 3
a = 6.53 m/s² downwards
Therefore, the acceleration of the bucket is 6.53 m/s² downwards
The net force must be zero
This is in accordance to Newton's first law, which states that any object in motion will remain in motion and any object at rest will remain at rest unless acted upon by an unbalanced force. An unbalanced force is one where the net force is not zero. If no unbalanced force is applied to a moving object, it will keep moving forever. The reason that we do not observe this in our daily lives is due to friction acting as the unbalanced force.
