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WARRIOR [948]
3 years ago
14

A 1.00-L flask was filled with 2.00 moles of gaseous and 2.00 moles of gaseous and heated. After equilibrium was reached, it was

found that 1.21 moles of gaseous was present. Assume that the reaction
SO2 + NO2 ⇌ SO3 + NO

occurs under these conditions. Calculate the value of the equilibrium constant, K, for this reaction.
Chemistry
1 answer:
Bogdan [553]3 years ago
6 0

Answer:

2.35

Explanation:

<em>A 1.00-L flask was filled with 2.00 moles of gaseous SO₂ and 2.00 moles of gaseous NO₂ and heated. After equilibrium was reached, it was found that 1.21 moles of gaseous NO was present. Assume that the reaction </em>

<em>SO₂ + NO₂ ⇌ SO₃ + NO </em>

<em>occurs under these conditions. Calculate the value of the equilibrium constant, K, for this reaction.</em>

<em />

Step 1: Calculate the molar concentrations

Since the reaction takes place in a 1.00 L flask, the molar concentrations are:

[SO₂]i = 2.00 M

[NO₂]i = 2.00 M

[NO]eq = 1.21 M

Step 2: Make an ICE chart

        SO₂ + NO₂ ⇌ SO₃ + NO

I       2.00   2.00       0        0

C        -x       -x         +x       +x

E    2.00-x  2.00-x    x         x

Step 3: Calculate the concentrations at equilibrium

The concentration of NO at equilibrium is 1.21 M. Then, x = 1.21.

[SO₂]eq = 2.00-1.21 = 0.79 M

[NO₂]eq = 2.00-1.21 = 0.79 M

[SO₃]eq = x = 1.21 M

[NO]eq = x = 1.21 M

Step 4: Calculate the value of the equilibrium constant, K, for this reaction

K = [SO₃] × [NO]/[SO₂] × [NO₂]

K = 1.21²/0.79² = 2.35

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8 0
4 years ago
1.505 times 10^23 Na atoms
dybincka [34]

5.75g

Explanation:

Given parameters:

Number of atoms = 1.505 x 10²³atoms

let us find the number of moles and mass of this atom.

Solution:

The mole is convenient unit for reporting measurements in chemistry. It allows us to make mathematical calculations:

     one mole of substance contains 6.02 x 10²³atoms

Number of moles of Na given = \frac{1.505 x 10^{23} }{6.02 x 10^{23} }  = 0.25moles

Mass of Na atom given = number of moles x molar mass

   Molar mass of Na= 23g/mole

Mass of Na = 0.25 x 23 = 5.75g

learn more:

Number of moles brainly.com/question/1841136

#learnwithBrainly

8 0
3 years ago
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