What mass of Na2CO3 is required to create 750 mL of an aqueous solution where the concentration of the carbonate (CO3-2) ions is
1.75 M? (assume complete dissociation)
1 answer:
Answer:
139.11 grams
Explanation:
The molarity (M) is equal to m (moles) /L (liters).
Notice how it is in mL so converting it would be 0.75 L (750*10-3)
Now plug in the information
1.75=m/0.75
m=1.3125
Now m is in moles so convert to grams to get the mass
1.3125 mol Na2CO3 * 105.9888 g Na2CO3 = 139.1103
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Approximate molecular masses:
Molecular mass of C = 12
Molecular mass of H = 1
Let n = moles required for CH₂.
Then
nCH₂ = 98
n(12 + 2*1) = 98
14n = 98
n = 7
Answer: The molecular formula is 7CH₂
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