What is the volume of a solution that has a molarity of 0.600M and contains 4.50 grams of NH4OH?

Chemistry

1 answer:

wariber [46]3 years ago

7 0

Answer:

The volume is 214, 3 ml

Explanation:

We calculate the weight of 1 mol of NH4OH:

Weight 1 mol NH4OH= Weight N + (Weight H) * 5 + Weight 0

Weight 1 mol NH4OH= 14g + 1 g* 5 + 16g = 35 g/mol

1 mol NH4OH-----35 g

0,6mol NH4OH----X=(0,6mol NH4OHx 35 g)/1 mol NH4OH= 21 g

We have 0,6 mol in 1000ml of solution (0,600 M)

21g NH4OH-----------1000ml

4,50 g NH4OH------x= (4,50 g NH4OH x 1000ml)/21 g NH4OH= 214, 2857143 ml

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