Question

Two infinite parallel surfaces carry uniform charge densities of 0.20 nC/m2 and -0.60 nC/m2. What is the magnitude of the electric field at a point between the two surfaces?

Answer 1

Answer:

Electric field, E = 45.19 N/C

Explanation:

It is given that,

Surface charge density of first surface, $\sigma_1=0.2\ nC/m^2=0.2\times 10^{-9}\ C/m^2$

Surface charge density of second surface, $\sigma=-0.6\ nC/m^2=-0.6\times 10^{-9}\ C/m^2$

The electric field at a point between the two surfaces is given by :

$E=\dfrac{\sigma}{2\epsilon_o}$

$E=\dfrac{\sigma1-\sigma_2}{2\epsilon_o}$

$E=\dfrac{0.2\times 10^{-9}-(-0.6\times 10^{-9})}{2\times 8.85\times 10^{-12}}$

E = 45.19 N/C

So, the magnitude of the electric field at a point between the two surfaces is 45.19 N/C. Hence, this is the required solution.