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krek1111 [17]
3 years ago
11

Use the graph to answer the question.

Physics
2 answers:
Setler79 [48]3 years ago
5 0

Answer:175

Explanation:

Murljashka [212]3 years ago
5 0

Answer:

the answer is 562.5m

Explanation:

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PLEASE HELP ME
sashaice [31]

Given that,

Electrical energy of the motor = 2280 J

Kinetic energy = 1606 J

Wasted energy in thermal and sound energy = 550 J

To find,

The efficiency of the motor in percent.

Solution,

Efficiency is defined as the ratio of useful output energy to the total energy.

Total energy = 2280 J

Useful energy = 1606 J

\eta=\dfrac{1606}{2280}\times 100\\\\=70.43\%

So, the efficiency of the motor is 70.43%.

5 0
3 years ago
Mike enters a revolving door that is not moving. explain where and how mike should push to produce a torque with the least amoun
Bingel [31]

Mike enters a revolving door that is not moving. Mike should push at the edge of the door where it is largest distance from the pivot point in order to produce a torque with the least amount of force. Torque is equal to t = force x distance.

7 0
4 years ago
Read 2 more answers
Suppose the rocket in the Example was initially on a circular orbit around Earth with a period of 1.6 days. Hint (a) What is its
ruslelena [56]

Answer:

a

The orbital speed is v= 2.6*10^{3} m/s

b

The escape velocity of the rocket is  v_e= 3.72 *10^3 m/s

Explanation:

Generally angular velocity is mathematically represented as

            w = \frac{2 \pi}{T}

Where T is the period which is given as 1.6 days = 1.6 *24 *60*60 = 138240 sec

       Substituting the value

         w = \frac{2 \pi}{138240}

             = 4.54*10^ {-5} rad /sec

At the point when the rocket is on a circular orbit  

   The gravitational force =  centripetal force and this can be mathematically represented as

              \frac{GMm}{r^2} = mr w^2

Where  G is the universal gravitational constant with a value  G = 6.67*10^{-11}

            M is the mass of the earth with a constant value of M = 5.98*10^{24}kg

            r is the distance between earth and circular orbit where the rocke is found

               Making r the subject

                     r = \sqrt[3]{\frac{GM}{w^2} }

                        = \sqrt[3]{\frac{6.67*10^{-11} * 5.98*10^{24}}{(4.45*10^{-5})^2} }

                        = 5.78 *10^7 m

The orbital speed is represented mathematically as

                   v=wr

Substituting value

                  v= (5.78*10^7)(4.54*10^{-5})

                     v= 2.6*10^{3} m/s    

The escape velocity is mathematically represented as

                            v_e = \sqrt{\frac{2GM}{r} }

Substituting values

                             = \sqrt{\frac{2(6.67*10^{-11})(5.98*10^{24})}{5.78*10^7} }

                             v_e= 3.72 *10^3 m/s

7 0
3 years ago
What is the acceleration of a 45 kg mass pushed with 15 N of force? What is the acceleration if the force changes to 25 N? What
Rama09 [41]
F = ma
Rearrange this so acceleration is the subject:
A = f/m

Now input your values into this equation for the first question :
A = f/m
A = 15/45
A = 0.33333333 m/s

Then using this same equation change the force of 15 to 25 :
A = f/m
A = 25/45
A = 0.55555556 m/s

For the last question keep the force of 15N but change the mass to 70kg into the same equation :
A = f/m
A = 15/70
A = 0.21 m/s (rounded)
8 0
3 years ago
Read 2 more answers
1. A bicycle initially moving with a velocity
ki77a [65]

Answer:

\boxed {\boxed {\sf 15 \ m/s \ or \ 15 \ m*s^{-1}}}

Explanation:

We are asked to find the final velocity. We are given the acceleration, time, and initial velocity, so we can use the following kinematics formula.

v_f= v_i+ at

In this formula, v_f is the final velocity, v_i is the initial velocity, a is the acceleration, and t is the time.

The bicycle has an initial velocity of 5.0 m *s⁻¹ or m/s, acceleration of 2 m/s², and a time of 5 seconds.

\bullet \  v_i = 5.0 \ m/s \\\bullet \  a= 2\ m/s^2\\\bullet \  t= 5  \ s

Substitute the values into the formula.

v_f=5.0 \ m/s + ( 2\ m/s^2 * 5 \ s)

Solve inside the parentheses.

  • \frac {2 \ m}{s^2}* 5 \ s = \frac{ 2 \ m}{s} * 5 = \frac{ 10 \ m}{s} = 10 \ m/s

v_f= 5.0 \ m/s + (10 \ m/s)

Add.

v_f= 15 \ m/s

The units can also be written as:

v_f= 15 \ m*s^{-1}

The bicycle's final velocity is 15 meters per second.

7 0
3 years ago
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