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soldi70 [24.7K]
3 years ago
9

A resistance of 1kΩ has a current of 0.25A throughout it when it is connected to the terminal of a battery. What is the potentia

l difference across the ends of a resistor?
Physics
1 answer:
pickupchik [31]3 years ago
6 0

Answer:

The potential difference across the resistor is 250 volts.

Explanation:

The potential difference V across the ends of the resistor is given by

V = IR

where I is the current through the resistor and R is is its resistance.

Now, in our case

R = 1.0*10^3\Omega,

I = 0.25 A;

therefore, the potential across is

V = 0.25A (1.0*10^3\Omega)

\boxed{V = 250volts.}

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Answer:

As given in the problem statement

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v(t) = 5sin(2 \pi 1000t) + 0.05sin(2 \pi 3000t)

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Sonbull [250]

Answer:

[ 2.67 , 1 ] m

Explanation:

Given:-

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                             a = Base , b = Perpendicular , c = Hypotenuse

- All rods are made of same material with uniform density. With  

Find:-

Find the coordinates of the center of mass of the triangle.

Solution:-

- The center of mass of any triangle is at the intersection of its medians.

- So let’s say we have a triangle with vertices at points (0,0) , (a,0) , and (0,b).

  • Median from (0,0) to midpoint (a/2,b/2) of opposite side has equation:

                                       bx−ay=0

  • Median from (a,0) to midpoint (0,b/2) of opposite side has equation:

                                      bx+2ay=ab

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                                     2bx+ay=ab

  • Solve all three equations simultaneously:

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                                     bx = b/3

                                     x = a / 3

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- So the coordinates of the centroid for right angle triangle would be:

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Use the graph below to answer the following question: if average acceleration is calculated using the equation, “ change in velo
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Answer:

a=9\ cm/s^2

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<u>Average Acceleration </u>

Acceleration is a physical magnitude defined as the change of velocity over time. When we have experimental data, we can compute it by calculating the slope of the line in velocity vs time graph.

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Answer:

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