Answer:
n.6 is T
Explanation:
because mass always stays the same where ever you are but weight changes depending on the gravity
Let say the point is inside the cylinder
then as per Gauss' law we have

here q = charge inside the gaussian surface.
Now if our point is inside the cylinder then we can say that gaussian surface has charge less than total charge.
we will calculate the charge first which is given as


now using the equation of Gauss law we will have


now we will have

Now if we have a situation that the point lies outside the cylinder
we will calculate the charge first which is given as it is now the total charge of the cylinder


now using the equation of Gauss law we will have


now we will have
Answer:
Force = 150 Newton.
Explanation:
Given the following data;
Mass = 60kg
Acceleration = 2.5m/s²
To find the force;
Force = mass * acceleration
Force = 60 * 2.5
Force = 150 Newton.
Therefore, the force required to accelerate this mass is 150 Newton.
It depends on the length of the pendulum and the strength of gravitational pull acting upon the pendulum.
Hope this helps!
<span>(1) Connect one red clamp to the positive (+) battery post of the "dead" battery.(2) Connect the other red clamp to the positive (+) post of the good battery.(3) Connect one black-end clamp to the negative (-) post of the good battery.(4) Carefully connect the other black-end clamp to some large metallic part of your car's engine block. Never connect it to the negative (-) post of the "dead" battery because this causes sparking which could ignite battery gases.<span>hope this helps </span></span>