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matrenka [14]
3 years ago
5

What is the difference between displacement and double displacement reactions?

Chemistry
1 answer:
steposvetlana [31]3 years ago
3 0
<u><em>Displacement reactions:
</em></u><em>it is the type of reaction in which reaction starts with the help of two compounds,,, but in the product the reactant that was initially with 1st compound joins with the 2nd compound..
</em><em>                     A+BC</em>⇒<em>AC+B
<u>example:
</u>Fe+CuSO4
</em>⇒<em>Cu+FeSO4</em><em>
</em><u><em>Double displacement reactions:
</em></u><em>while it is the type of reaction in which one product is obtained parts of both reacting compounds interchange with each other..
</em><u><em></em></u><em>             AB+CD</em>⇒<em>AD+BC</em><em>
<u>example:
</u>AgNO3+NaCl
</em>⇒<em>AgCl+NaNO3.....:)</em><em><u>
</u>
</em><em></em><u><em>
</em></u>
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Answer:

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Explanation:

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3 years ago
How long, in seconds, would it take for the concentration of A to decrease from 0.860 M to 0.310 M?
kogti [31]

Answer:

2.038 seconds.

Explanation:

So, in the question above we are given the following parameters in order to solve this question. We are given a rate constant of 0.500 s^-, initial concentration= 0.860 M and final concentration= 0.310 M,the time,t =??.

Assuming that the equation for the first order of reaction is given below,that is;

A ---------------------------------> products.

Recall the formula below;

B= B° e^-kt.

Therefore, e^-kt = B/B°.

-kt = ln B/B°.

kt= ln B°/B.

Where B° and B are the amount of the initial concentration and the amount of the concentration remaining, k is the rate constant and t = time taken for the concentration to decrease.

So, we have; time taken,t = ln( 0.860/.310)/0.500.

==> ln 2.77/0.500.

==> time taken,t =2.038 seconds.

6 0
3 years ago
Calcium phosphate reacts with sulfuric acid to form calcium sulfate and phosphoric acid. What is the coefficient for sulfuric ac
gregori [183]

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<h2>explanation</h2>

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that is

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since coefficient is number in front of a chemical formula  the coefficient of H2SO4 is 3

8 0
3 years ago
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