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Darya [45]
3 years ago
9

A sample contains 16 mg of polonium-218. After 12 minutes, the sample will contain 1.0 mg of polonium-218. What is the half life

of polonium-218?
Chemistry
1 answer:
mariarad [96]3 years ago
5 0

Answer:

Half-life = 3 minutes

Explanation:

Using the radioactive decay equation we can solve for reaction constant, k. And by using:

K = ln2 / Half-life

We can find half-life of polonium-218

Radioactive decay:

Ln[A] = -kt + ln [A]₀

Where:

[A] could be taken as mass of polonium after t time: 1.0mg

k is Reaction constant, our incognite

t are 12 min

[A]₀ initial amount of polonium-218: 16mg

Ln[A] = -kt + ln [A]₀

Ln[1.0mg] = -k*12min + ln [16mg]

-2.7726 = - k*12min

k = 0.231min⁻¹

Half-life = ln 2 / 0.231min⁻¹

<h3>Half-life = 3 minutes</h3>

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You have 10.0 g each of Na, C, Pb, Cu and Ne. Which contains the smallest number of moles? You have 10.0 g each of Na, C, Pb, Cu
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The answer to your question is number 1. Pb

Explanation:

Data

10 grams of Na, C, Pb, and Ne

Process

Calculate the moles of each element

                        23 g of Na ----------------- 1 mol

                        10 g of Na ------------------- x

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                        20 g of Ne ---------------- 1 mol

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                            10 g of Pb -------------- x

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