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zalisa [80]
3 years ago
6

A population of large predator

Chemistry
2 answers:
kicyunya [14]3 years ago
7 0

Answer:

Negatively

Explanation:

As the Predators population increases the preys population decreases

dangina [55]3 years ago
3 0

Answer:

they will eat a lot of fish and make other animals go hungry

Explanation:

logic

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A 75 um thick polysulphone microporous membrane has an average porosity of E 0.35. Pure water flux through the membrane is 35 m'
Paul [167]

Explanation:

The given data is as follows.

           Water flux, J_{w} = 25 m^{3}/m^{2}h

                                       = \frac{25}{3600} m^{3}/m^{2}h

So, let velocity (u) = \frac{25}{3600} m/s = 6.9 \times 10^{-3}

             \rho = 998 kg/m^{3}

             Pore size, d = 0.8 \times 10^{-6} m

             \mu = 0.9 cP = 9 \times 10^{-4} Pa.s

Hence, calculate the reynold number as follows.

                 R_{e} = \frac{\rho \times u \times d}{\mu}            

                        = \frac{998 kg/m^{3} \times 6.9 \times 10^{-3} \times 0.8 \times 10^{-6} m}{9 \times 10^{-4} Pa.s}    

                        = 612.1 \times 10^{-5}

                        = 0.006

This means that the flow is laminar.

Now, we use Hagen-Poiseuille equation as follows.

             J_{w} = \frac{\varepsilon \times d^{2}}{32 \times \mu \times \tau} \times \frac{\Delta P}{L_{m}}

where,     \varepsilon = membrane porosity = 0.35

                              d = 0.8 \times 10^{-6} m

                       \Delta P = 2 \times 10^{5} Pa

                      \mu = 9 \times 10^{-4}

                      \tau = tortuosity

                      L_{m} = membrane thickness = 75 \times 10^{-6} m

                    \frac{25}{3600} = \frac{0.35 \times (0.8 \times 10^{-6})}{32 \times (9 \times 10^{-4}) \times \tau}

                            \tau = 3.73

Hence, the tortuosity factor of the pores is 3.73.

As flow resistance = R_{m}

               J_{w} = \frac{\Delta P}{r \times R_{m}}

               R_{m} = 3.2 \times 10^{10} m^{-1}

Water permeability is represented by L_{p}.

                    J_{w} = L_{p} \times \Delta P  

             6.9 \times 10^{-3} = L_{p} \times 2 \times 10^{5} Pa  

              L_{p} = 3.45 \times 10^{-8} m^{3}/m^{2}s Pa

Therefore, the resistance to flow is 3.2 \times 10^{10} m^{-1} and its water permeability is 3.45 \times 10^{-8} m^{3}/m^{2}s Pa.

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djyliett [7]

Answer:Correct

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Because the density of the egg is higher than the density of tap water, so it sinks.
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Neutrons were discovered by James Chadwick<span> in 1932, when he demonstrated that penetrating radiation incorporated beams of neutral particles. Neutrons are located in the nucleus with the protons. Along with protons, they make up almost all of the mass of the </span>atom<span>.

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