The vapor pressure is obtained as 23.47 torr.
<h3>What is the vapor pressure?</h3>
Given that; p = x1p°
p = vapor pressure of the solution
x1 = mole fraction of the solvent
p° = vapor pressure of the pure solvent
Δp = p°(1 - x1)
Δp =x2p°
Δp = vapor pressure lowering
x2 = mole fraction of the of the solute
Number of moles of glycerol = 32.5 g/92 g/mol = 0.35 moles
Number of moles of water = 500.0 g/18 g/mol = 27.8 moles
Total number of moles = 0.35 moles + 27.8 moles = 28.15 moles
Mole fraction of glycerol = 0.35 moles/28.15 moles = 0.012
Mole fraction of water = 27.8 moles/28.15 moles =0.99
Δp = 0.012 * 23.76 torr
Δp = 0.285 torr
p1 = p° - Δp
p1 = 23.76 torr - 0.285 torr
p1 = 23.47 torr
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Denitrification is part of the nitrogen cycle
Answer:
See explanation
Explanation:
The question is incomplete but i will try to give you all the necessary guide that you need in order to answer the question.
When compounds are formed, atoms exchange valency. The valency of nitrogen is three while that of the metal is two. The exchange yields M3N2.
If the compound has been specifically mentioned to be a metal, then it must be a group two element. It could be any of Mg, Ca, Sr, Ba or Ra. I did not mention Be here because most of its compounds are covalent.
This will help you to answer the complete question.
Answer:
9.133×10^-6 m
Explanation:
A photon is the smallest discrete amount or quantum of electromagnetic radiation. It is the basic unit of all light. Photons are always in motion and, in a vacuum, travel at a constant speed to all observers of 3 x 10^8 m/s.
From the question, the following details were supplied;
Energy of the photon (E) = 4.61×10^−19 J
Speed of light (c) = 2.99×10^8 m/s
Plank's constant (h) = 6.626×10^−34 J⋅s
Wavelength of the photon (λ)= ??? The unknown
From
E=hc/λ
λ= hc/E
Substituting values
λ= 6.626×10^−34 × 2.99×10^8/ 4.61×10^−19
λ= 91.33×10^-7 m
λ= 9.133×10^-6 m
Answer: All the circuits have energy source, wires and device that needs electrical energy in common.
Explanation: Electric circuit is a path through which electrons flow from higher potential to lower potential.
A wire is required to connect Energy source and a device that needs electrical energy to run. On the other hand, voltmeter and ammeter are the devices which are used to measure voltage and current respectively and not necessarily used in all the circuits.
Hence, the common components in an electric circuit are energy source, wires and device that needs electrical energy in common.
