Answer: A volume of 455 mL from 0.550 M KBr solution can be made from 100.0 mL of 2.50 M KBr.
Explanation:
Given: = ?,
= 0.55 M
= 100.0 mL,
= 2.50 M
Formula used to calculate the volume of KBr is as follows.
Substitute the values into above formula as follows.
Thus, we can conclude that a volume of 455 mL from 0.550 M KBr solution can be made from 100.0 mL of 2.50 M KBr.
Answer:
Explanation:
Hello,
In this case, the reaction is:
Thus, the law of mass action turns out:
Thus, since at the beginning there are 29 moles of ethylene and once the equilibrium is reached, there are 16 moles of ethylene, the change result:
In such a way, the equilibrium constant is then:
Thereby, the initial moles for the second equilibrium are modified as shown on the denominator in the modified law of mass action by considering the added 15 moles of ethylene:
Thus, the second change, finally result (solving by solver or quadratic equation):
Finally, such second change equals the moles of ethanol after equilibrium based on the stoichiometry:
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