Answer:
The answer is
<h2>1.0 g/cm³</h2>
Explanation:
The density of a substance can be found by using the formula

From the question
mass = 10 g
volume = 10 cm³
It's density is

We have the final answer as
<h3>1.0 g/cm³</h3>
Hope this helps you
it would be heating of 32g of s and 56g of Fe to produce 88g of FeS and unused reactants
The mass of chlorine required to react with 10.0 g of sodium metal to produce sodium chloride is 15.26 g.
The balanced chemical reaction is :
<em> 2Na + Cl₂ → 2NaCl</em>
<em />
Given data :
Mass of sodium = 10.0 g
Number of moles of Na -
Number of moles = <u> Given mass </u>
Molar mass
Number of moles = <u> 10.0 g</u> = 0.43 mol
23 g
Comparing moles of Na and Cl₂ from the balanced chemical equation,
Na : Cl₂
2 : 1
0.43 : <u> 1 </u> x 0.43 = 0.215 mol
2
Mass of chlorine gas :
(molar mass of chlorine = 71 g)
Mass of chlorine = number of moles x molar mass
Mass = 0.215 mol x 71 g/mol
= 15.26 g
To learn more about sodium and chlorine,
brainly.com/question/14588368
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Answer : The rate of the reaction if the concentration of
is doubled is, 0.006 M/s
Explanation :
Rate law : It is defined as the expression which expresses the rate of the reaction in terms of molar concentration of the reactants with each term raised to the power their stoichiometric coefficient of that reactant in the balanced chemical equation.
The balanced equations will be:

In this reaction,
and
are the reactants.
The rate law expression for the reaction is:
![\text{Rate}=k[CH_3Br][NaOH]](https://tex.z-dn.net/?f=%5Ctext%7BRate%7D%3Dk%5BCH_3Br%5D%5BNaOH%5D)
As we are given that:
= concentration of
= 0.100 M
= concentration of
= 0.100 M
Rate = 0.0030 M/s
Now put all the given values in the above expression, we get:


Now we have to calculate the rate of the reaction if the concentration of
is doubled.
![\text{Rate}=k[CH_3Br][NaOH]](https://tex.z-dn.net/?f=%5Ctext%7BRate%7D%3Dk%5BCH_3Br%5D%5BNaOH%5D)


Thus, the rate of the reaction if the concentration of
is doubled is, 0.006 M/s