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Alika [10]
3 years ago
14

A sphere with radius 1 m has temperature 18°C. It lies inside a concentric sphere with radius 2 m and temperature 25°C. The temp

erature at a distance r from the common center of the spheres satisfies the differential equation below. If we let S = dT/dr, then S satisfies a first-order differential equation. Solve it to find an expression for the temperature T(r) between the spheres.
Chemistry
1 answer:
gladu [14]3 years ago
4 0

Answer:

The expression will be T=7r

Explanation:

From equation S=dT/dr, we can solve this equation by integrating it and usig the values 25C and 18C for T and 2 and 1 for the radius. The solution to the integration will result in the value for S. For this example, it will be 7. Therefore, the main expression will be T= 7r in which the temperature is in fuction of the radius between the spheres.

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Change in the amount of volume left inside the basketball for the remaining air coming in
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3 years ago
calculate density of a rectangular solid, which has a mass of 25.71 g. It is 2.30 cm long, 4.01 cm wide and 1.82 cm high.
Levart [38]
Density is a property of the substances that is obtained by dividing its mass by the volume. For a rectangular solid, the volume may be solved by the following equation,
 
                                          V = L x W x H

Substituting the given values for the dimension,
 
                  V = (2.30 cm) x (4.01 cm) x (1.82 cm) = 16.78786 cm³

Calculating for the density,
 
                                Density = mass / volume
 
                Density = 25.71 cm / <span>16.78786 cm³ = 1.53 grams per cm</span>³

Thus, the density of the given solid is approximately 1.53 grams per cm³.




5 0
3 years ago
A gas sample has an initial pressure of 547 mmHg and initial volume of 0.500 L. Pressure (in atm) when the volume of the sample
Alenkasestr [34]
What are your answer choices?

8 0
4 years ago
What is the primary result of a fission
Rudik [331]

Answer:

(1) conversion of mass to energy

Explanation:

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8 0
3 years ago
The Density of pure carbon in Diamond form is 3.52 g/cm^3. How many cubic inches would 23.7 moles of pure diamond occupy?
Vedmedyk [2.9K]

Answer : The volume of pure diamond is 0.493inch^3

Explanation : Given,

Density of pure carbon in diamond = 3.52g/cm^3

Moles of pure diamond = 23.7 moles

Molar mass of carbon = 12 g/mol

First we have to calculate the mass of carbon or pure diamond.

\text{ Mass of carbon}=\text{ Moles of carbon}\times \text{ Molar mass of carbon}

Molar mass of carbon = 12 g/mol

\text{ Mass of carbon}=(23.7moles)\times (12g/mole)=284.4g

Now we have to calculate the volume of carbon or pure diamond.

Formula used:

Density=\frac{Mass}{Volume}

Now putting all the given values in this formula, we get:

3.52g/cm^3=\frac{284.4g}{Volume}

Volume = 80.8cm^3

As we know that:

1cm^3=0.061inch^3

So,

Volume = 0.061\times 80.8inch^3

Volume = 0.493inch^3

Therefore, the volume of pure diamond is 0.493inch^3

5 0
3 years ago
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