<u>Answer:</u> The reaction order with respect to A is 'm'
<u>Explanation:</u>
Order of the reaction is the sum of the concentration of terms on which the rate of the reaction actually depends. It is equal to the sum of the exponents of the molar concentration in the rate law expression.
Elementary reactions the reactions for which the order of the reaction is same as its molecularity and order with respect to each reactant is equal to its stoichiometric coefficient as represented in the balanced chemical equation.
The given chemical equation follows:

The rate of the above reaction is given to us as:
![Rate=k[A]^m[B]^n](https://tex.z-dn.net/?f=Rate%3Dk%5BA%5D%5Em%5BB%5D%5En)
In the above rate law expression, the order with respect to the reactants is not equal to the stoichiometric coefficients. Thus, it is not an elementary reaction.
Order with respect to reactant A = m
Order with respect to reactant B = n
Hence, the reaction order with respect to A is 'm'
Answer:
Heated water is more dense than melted snow because water as liquid is denser than ice. Ice floats on water, which means that it has less density than water. Heated water is warmer and more dense than melted ice.
Explanation:
Answer : The mass of oxygen combined with 1.00 g of carbon in carbon dioxide will be, 2.66 grams.
Explanation :
Law of multiple proportion : It states that when two elements can combine to form two or more different compounds then the mass of one element compared to fixed mass of the other will always be in a ratio of small whole numbers.
As we are given that the mass of ratio of carbon and oxygen in CO is 1 gram and 1.33 gram.
Ratio of C and O in CO = 1 : 1
Ratio of C and O in CO₂ = 1 : 2
So, the mass of ratio of carbon and oxygen in CO₂ will be 1 gram and (2×1.33) 2.66 gram.
Thus, the mass of oxygen combined with 1.00 g of carbon in carbon dioxide will be, 2.66 grams.
Answer:
b. some sodium iodide will precipitate out of solution
Explanation:
We know that for salts solubility decreases as the temperature of the solution decreases. So, NaI being a salt, its solubility will surely decrease when the temperature is cooled down to 25°C from 50°C.
Thus,the undissolved sodium iodide will precipitate out of the solution.