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3 years ago

What is the slope of AB?

Mathematics

2 answers:

Arada [10]3 years ago

4 0

-2/3 from A you go to the right 3 times which is 3 x and you go down 2 which is -2y

prohojiy [21]3 years ago

3 0

Answer: -2/3

Step-by-step explanation:

If you want to find the slope of something, the quick way is to use $\frac{rise}{run}$ .

In this situation, the “rise” (change in y axis) is -2 because it’s going down and the “run” (change in x axis) is 3. Therefore, it’s -2/3.

The formula to find slope is:

$\frac{y_{2}-y_{1}}{x_{2}-x_{1} }$

(I think, if I memorized it correctly)

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A coin, having probability p of landing heads, is continually flipped until at least one head and one tail have been flipped. (a

Natali [406]

Answer:

(a)

The probability that you stop at the fifth flip would be

$p^4 (1-p) + (1-p)^4 p$

(b)

The expected numbers of flips needed would be

$\sum\limits_{n=1}^{\infty} n p(1-p)^{n-1} = 1/p$

Therefore, suppose that $p = 0.5$ , then the expected number of flips needed would be 1/0.5 = 2.

Step-by-step explanation:

(a)

Case 1

Imagine that you throw your coin and you get only heads, then you would stop when you get the first tail. So the probability that you stop at the fifth flip would be

$p^4 (1-p)$

Case 2

Imagine that you throw your coin and you get only tails, then you would stop when you get the first head. So the probability that you stop at the fifth flip would be

$(1-p)^4p$

Therefore the probability that you stop at the fifth flip would be

$p^4 (1-p) + (1-p)^4 p$

(b)

The expected numbers of flips needed would be

$\sum\limits_{n=1}^{\infty} n p(1-p)^{n-1} = 1/p$

Therefore, suppose that $p = 0.5$ , then the expected number of flips needed would be 1/0.5 = 2.

7 0

2 years ago

What is the value of x (x+2)(x-3)=0

wolverine [178]

Answer:

x = 3 or x = -2

Step-by-step explanation:

Solve for x over the real numbers:

(x + 2) (x - 3) = 0

Hint: | Find the roots of each term in the product separately.

Split into two equations:

x - 3 = 0 or x + 2 = 0

Hint: | Look at the first equation: Solve for x.

Add 3 to both sides:

x = 3 or x + 2 = 0

Hint: | Look at the second equation: Solve for x.

Subtract 2 from both sides:

Answer: x = 3 or x = -2

8 0

3 years ago

List the first 5 muliples

IceJOKER [234]

11: 22,33,44,55 8: 16,24,32,40,48 2: 4,6,8,10,12

6 0

3 years ago

Which steps could be part of the process in algebraically solving the system of equations, y + 5x = x2 + 10 and y = 4x – 10? Che

guapka [62]

That would be :
4x – 10 = x2 – 5x + 10 ( y = 4x - 10 is substitute for y)

PROOF: y + 5x = x² + 10
 (4x - 10) + 5x = x² + 10
4x - 10 = x² -5x + 10


0 = x2 – 9x + 20 (liked terms are grouped and simplified)

PROOF: 4x - 10 = x² -5x + 10
4x = x² -5x + 10 + 10
0 = x² -5x -4x + 20
0 = x² - 9x + 20

Solving:
x² - 9x + 20 = 0

x² - 5x - 4x + 20 = 0

(x - 5) (x - 4) = 0

⇒ x = 4 (as question says) OR x = 5

8 0

3 years ago

Read 2 more answers

Find all of the points of the form (x −1) which are 4 unit from the point (3,2)

Bond [772]

Answer:

$(3+2\sqrt{2},2+2\sqrt{2}),(3-2\sqrt{2},2-2\sqrt{2})$

Step-by-step explanation:

$Points\ are\ of\ the\ form\ (x,x-1)\\\\Distance\ of\ these\ points\ from\ (3,2)=4\\\\\sqrt{(x-3)^2+(x-3)^2}=4\\\\\sqrt{(x-3)^2+(x-1-2)^2}=4\\\\\sqrt{2(x-3)^2}=4\\\\2(x-3)^2=16\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ square\ both\ the\ sides\\\\(x-3)^2=\frac{16}{2}\\\\(x-3)^2=8\\\\(x-3)=\pm 2\sqrt{2}\ \ \ \ \ \ \ \ \ \ \ square\ root\ both\ the\ sides\\\\x=3\pm 2\sqrt{2}\\\\When\ x=3+2\sqrt{2}\ \ \Rightarrow x-1=3+2\sqrt{2}-1=2+2\sqrt{2}\\\\When\ x=3-2\sqrt{2}\ \ \Rightarrow x-1=3-2\sqrt{2}-1=2-2\sqrt{2}$

4 0

2 years ago