Molarity is defined as the moles of solute per liter of solution.
. Where M is molarity, n is the number of moles and V is the volume. First we must find the molar mass of
which is 109.98 g/mol
![Li_2SO_4= 2 \times Li_{Ar} + S_{Ar} + 4 \times O_{Ar}\\= (2 \times 6.941 + 32.1 + 4 \times 16.0) = 109.98 g/mol](https://tex.z-dn.net/?f=Li_2SO_4%3D%202%20%5Ctimes%20Li_%7BAr%7D%20%2B%20S_%7BAr%7D%20%2B%204%20%5Ctimes%20O_%7BAr%7D%5C%5C%3D%20%282%20%5Ctimes%206.941%20%2B%2032.1%20%2B%204%20%5Ctimes%2016.0%29%20%3D%20109.98%20g%2Fmol)
![820\ g\ Li_2SO_4 \times \frac{mol}{109.98\ g}= 7.46\ mol\ Li_2SO4](https://tex.z-dn.net/?f=820%5C%20g%5C%20Li_2SO_4%20%5Ctimes%20%5Cfrac%7Bmol%7D%7B109.98%5C%20g%7D%3D%207.46%5C%20mol%5C%20Li_2SO4)
Then we find the molarity using above equation
![M= \frac{n}{V} = \frac{7.46 mol}{2500ml} \times\frac{1000ml}{L} = 2.98\ M](https://tex.z-dn.net/?f=M%3D%20%5Cfrac%7Bn%7D%7BV%7D%20%3D%20%5Cfrac%7B7.46%20mol%7D%7B2500ml%7D%20%5Ctimes%5Cfrac%7B1000ml%7D%7BL%7D%20%3D%202.98%5C%20M)
It would take 8 antacid tablets to produce 120 mL of CO2 gas.
No, the properties of a substance are not affected by the amount of a substance.
Three classes: 28×3=84 students
8 test tubes per student: 84× 8= 672
hope this helps!
Answer:
100g / (5.2g/cm3)
= 100g / (5.2g / 1cm3)
= 100g x 1cm3 / 5.2 g
= 19.2 cm3
Since 1 cm3 = 1 ml, your answer is 19.2 ml.