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Kay [80]
3 years ago
5

A white powder is made of 24% carbon and the rest being Fluorine. Its simplest formula is. (C=12, F=19)

Chemistry
1 answer:
ladessa [460]3 years ago
7 0

Answer:

A. CF2

Explanation:

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What is the molarity of a solution prepared by dissolving 10.0g of kno3 in 250 ml of solution
maw [93]

Answer:

Mass of KNO3= 10g

Molar mass of KNO3 = 101.1032g/mol

Volume = 250ml = 0.25L

No of mole on of KNO3 = mass of KNO3/Molar mass of KNO3

no of mole of KNO3 = 10/101.1032

No of mole of KNO3 = 0.09891

molarity of KNO3 = no of mole of KNO3/Vol (L)

Molarity = 0.09891/0.25 = 0.3956M

Molarity of KNO3 = 0.3956M

8 0
3 years ago
A gas at 200 K occupies a volume of 350 ml. What temperature is needed to increase the volume
Rudik [331]

Answer: Temperature in constant pressure is 286 K

Explanation: If pressure remains constant, then V/T = constant.

V1 = 350 ml and T1 = 200 K and V2 = 500 ml.  V1/T1 = V2/T2

and T2 = T1· V2 / V1 = 200 K · 500 ml / 300 ml = 285,7 K

5 0
3 years ago
There are two binary compounds of mercury and oxygen. heating either of them results in the decomposition of the compound, with
grandymaker [24]

\text{Hg} \text{O} and \text{Hg}_{2} \text{O}.

Assuming complete decomposition of both samples,

  • m(\text{Hg}) = m(\text{residure})
  • m(\text{O}) = m(\text{loss})

First compound:

  • m(\text{O}) = m(\text{loss}) = 0.6498 - 0.6018 = 0.048 \; g
  • m(\text{Hg}) = m(\text{residure}) = 0.6018 \; g

n = m/M; 0.6498 \; g of the first compound would contain

  • n(\text{O atoms}) = 0.048 \; g  / 16 \; g \cdot mol^{-1}= 0.003 \; mol
  • n(\text{Hg atoms}) = 0.6018 \; g  / 200.58 \; g \cdot mol^{-1}= 0.003 \; mol

Oxygen and mercury atoms seemingly exist in the first compound at a 1:1 ratio; thus the empirical formula for this compound would be \text{Hg} \text{O} where the subscript "1" is omitted.

Similarly, for the second compound

  • m(\text{O}) = m(\text{loss}) = 0.016 \; g
  • m(\text{Hg}) = m(\text{residure}) = 0.4172 - 0.016 = 0.4012  \; g

n = m/M; 0.4172 \; g of the first compound would contain

  • n(\text{O atoms}) = 0.016 \; g  / 16 \; g \cdot mol^{-1}= 0.001 \; mol
  • n(\text{Hg atoms}) = 0.4012 \; g  / 200.58 \; g \cdot mol^{-1}= 0.002 \; mol

n(\text{Hg}) : n(\text{O}) \approx  2:1 and therefore the empirical formula

\text{Hg}_{2} \text{O}.

8 0
3 years ago
The property of metals to be made into wire is called
ANEK [815]

Metal have some properties like lustrous (shiny), good conductors of electricity and heat,etc. Metals have another property by which metal can be drawn into a wire by hammering on it .This property is called as 'ductility'.

hope this helps, please mark brainliest. :)

6 0
2 years ago
Compare an ionic and a molecular compound in terms of how each is formed
GREYUIT [131]

Answer:

Molecular compounds are pure substances formed when atoms are linked together by sharing of electrons while ionic compounds are formed due to the transfer of electrons.

Molecular compounds are made due to covalent bonding while ionic compounds are made due to ionic bonding.

Explanation:

8 0
3 years ago
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