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Juliette [100K]
2 years ago
9

HELP ME

Mathematics
1 answer:
IRISSAK [1]2 years ago
3 0

Answer:

[-5,5; +∞)

Step-by-step explanation:

according to the given grid the vertex of the parabola is (-0,5; -5,5).

The domain of f is: [-5,5; +∞)

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What is the slope of the line, y=5−4x?
hoa [83]

Answer:

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ΔY

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Step-by-step explanation:

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25 pt question amd will mark brainliest
Usimov [2.4K]
Hello!

The angles are supplementary meaning they add to 180°

a + 2a + 3 = 180

Combine like terms

3a + 3 =  180

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Hope this helps!
8 0
2 years ago
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Assume that a sample is used to estimate a population proportion μ . Find the margin of error M.E. that corresponds to a sample
hichkok12 [17]

Answer:

MoE = 1.645\cdot \frac{13.1}{\sqrt{772} } \\\\MoE = 1.645\cdot 0.47147\\\\MoE = 0.776\\\\

Step-by-step explanation:

Since the sample size is quite large, we can use the z-distribution.

The margin of error is  given by

$ MoE = z_{\alpha/2}(\frac{s}{\sqrt{n} } ) $

Where n is the sample size, s is the sample standard deviation and z_{\alpha/2} is the z-score corresponding to a 90% confidence level.

The z-score corresponding to a 90% confidence level is

Significance level = α = 1 - 0.90= 0.10/2 = 0.05

From the z-table at α = 0.05

z-score = 1.645

MoE = 1.645\cdot \frac{13.1}{\sqrt{772} } \\\\MoE = 1.645\cdot 0.47147\\\\MoE = 0.776\\\\

Therefore, the margin of error is 0.776.

3 0
2 years ago
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stepladder [879]

Using it's concept, it is found that there is a 0.004 = 0.4% probability of a game console buyer buying a defective Suny Playcom.

<h3>What is a probability?</h3>

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In this problem, 40% of the consoles bought are of the Suny Playcom series, and of those, 1% are defective, hence the probability is given by:

p = 0.4 x 0.01 = 0.004

0.004 = 0.4% probability of a game console buyer buying a defective Suny Playcom.

More can be learned about probabilities at brainly.com/question/24808124

#SPJ1

3 0
1 year ago
Which description represents the expression 5 x−95 x−9 ?
guapka [62]
9 is subtracted from the sum of 5 and a number
6 0
3 years ago
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