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iogann1982 [59]
3 years ago
8

Which natural resource is renewable? coal wind topsoil O oil

Chemistry
2 answers:
ANEK [815]3 years ago
7 0

Answer:

Wind

Explanation:

the other ones you can only use once

Damm [24]3 years ago
7 0

the answer is easy :)

the answer is: wind

explaination: there is a limitless supply that is naturally produced. it provides clean, non-pulluting eletricity that businesses can use. besinesses can become more friendly to the enviorment by using wind power!

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Wenzhou prepares 200 mL of a solution of SnCl4in which the concentration ofchloride ions is 0.240M.a) What is the molarity of th
nalin [4]

Answer:  a) 0.06 M

b) 3.13 grams.

Explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per Liter of the solution.

Molarity=\frac{moles}{\text {Volume in L}}

Moles of  Cl^-=Molarity\times {\text {Volume in L}}=0.240\times 0.2L=0.048moles

The balanced reaction for dissociation will be:

SnCl_4\rightarrow Sn^{4+}+4Cl^{-}

Thus for 4 moles of Cl^-, there is 1 mole of SnCl_4

Thus moles of SnCl_4=\frac{1}{4}\times 0.048=0.012

Molarity of SnCl_4=\frac{moles}{\text {Volume in L}}=\frac{0.012}{0.2L}=0.06M

Thus the molarity of the  SnCl_4 solution = 0.06 M

b) Mass of SnCl_4= moles\times {\text {Molar mass}}=0.012mol\times 260.522g/mol=3.13g

Thus mass of  SnCl_4 Wenzhou use is 3.13 grams.

7 0
3 years ago
Read 2 more answers
A chemist prepares a solution of magnesium chloride MgCl2 by measuring out 49.mg of MgCl2 into a 100.mL volumetric flask and fil
Flura [38]

Answer:  Molarity of Cl^- anions in the chemist's solution is 0.0104 M

Explanation:

Molarity : It is defined as the number of moles of solute present per liter of the solution.

Formula used :

Molarity=\frac{n\times 1000}{V_s}

where,

n= moles of solute

Moles=\frac{\text{Given mass}}{\text{Molar mass}}=\frac{0.049g}{95g/mol}=5.2\times 10^{-4}moles  

V_s = volume of solution in ml = 100 ml

Now put all the given values in the formula of molarity, we get

Molarity=\frac{5.2\times 10^{-4}moles\times 1000}{100ml}=5.2\times 10^{-3}mole/L

Therefore, the molarity of solution will be 5.2\times 10^{-3}mole/L

MgCl_2\rightarrow Mg^{2+}+2Cl^-

As 1 mole of MgCl_2 gives 2 moles of Cl^-

Thus 5.2\times 10^{-3}  moles of MgCl_2 gives =\frac{2}{1}\times 5.2\times 10^{-3}=0.0104

Thus the molarity of Cl^- anions in the chemist's solution is 0.0104 M

6 0
3 years ago
Potassium hydrogen phthalate is a solid, monoprotic acid frequently used in the laboratory to standardize strong base solutions.
Troyanec [42]

Answer:

2.75 g

Explanation:

The number of moles of KOH is obtained from the equation;

n=CV

C= concentration

V= volume of solution

n= 0.527 × 25.6/1000

n= 0.0135

Reaction equation;

KOH(aq) + KHC8H4O4(aq) --->(KC8H4O4)K(aq) + H2O(l)

1 mole of KHP reacts with 1 mole of KOH

Hence; 0.0135 moles of KHP reacts with 0.0135 moles of KOH

From;

Number of moles = reacting mass/molar mass

Reacting mass = 0.0135 × 204

= 2.75 g of KHP

5 0
3 years ago
Polonium-218 undergoes beta decay, converting a neutron into a proton. Then the daughter isotope undergoes another beta decay, a
sergij07 [2.7K]

Answer: ^{218}_{84}Po \rightarrow ^{218}_{85}At + ^{0}_{-1}e is the correct equation for beta decay.

Explanation:

When a beta particle, that is, ^{0}_{-1}e is emitted in a radioactive decay then it is known as beta decay.

Therefore, beta decay of Polonium-218 is as follows.

^{218}_{84}Po \rightarrow ^{218}_{85}At + ^{0}_{-1}e

Therefore, we can conclude that ^{218}_{84}Po \rightarrow ^{218}_{85}At + ^{0}_{-1}e is the correct equation for the given beta decay.  

8 0
3 years ago
During a lab, you heat 1.62 g of a CoCl2 hydrate over a Bunsen burner. After heating, the final mass of the dehydrated compound
sashaice [31]
Answer is: formula of hydrate is CoCl₂· 6H₂O -c<span>obalt(II) chloride hexahydrate
</span>m(CoCl₂· xH₂O) = 1,62 g.
m(CoCl₂) = 0,88 g.
n(CoCl₂) = m(CoCl₂) ÷ M(CoCl₂)
n(CoCl₂) = 0,88 g ÷ 130 g/mol
n(CoCl₂) = 0,0068 mol.
m(H₂O) = 1,62 g - 0,88 g.
m(H₂O) = 0,74 g.
n(H₂O) = m(H₂O) ÷ m(H₂O) 
n(H₂O) = 0,74 g ÷ 18 g/mol
n(H₂O) = 0,041 mol.
n(CoCl₂) : n(H₂O) = 0,0068 mol : 0,041 mol.
n(CoCl₂) : n(H₂O) = 1 : 6.
8 0
4 years ago
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