The human gametes differ from all the other cells in the body because the somatic cells have a complete set of chromosomes
Answer:
337.22 K
Explanation:
Given that:
P₁ = 1 atm
T₁ = 350 K
P₂ = 0.639 atm
T₂ = ??? (unknown)
R(rate constant) = 8.34 J k⁻¹ mol⁻¹
Using Clausius-Clapeyron equation, we can determine the final boiling point of the process.
Clausius-Clapeyron equation can be written as:
![In\frac{P_2}{P_1}=\frac{\delta H_{vap}}{R}[\frac{T_2-T_1}{T_2T_1}]](https://tex.z-dn.net/?f=In%5Cfrac%7BP_2%7D%7BP_1%7D%3D%5Cfrac%7B%5Cdelta%20H_%7Bvap%7D%7D%7BR%7D%5B%5Cfrac%7BT_2-T_1%7D%7BT_2T_1%7D%5D)
Substituting our values given; we have:
![In\frac{0.639}{1}=(\frac{34.4*10^3J/mol}{8.314 J K^{-1}mol^{-1}})[\frac{T_2-350}{350T_2}]](https://tex.z-dn.net/?f=In%5Cfrac%7B0.639%7D%7B1%7D%3D%28%5Cfrac%7B34.4%2A10%5E3J%2Fmol%7D%7B8.314%20J%20K%5E%7B-1%7Dmol%5E%7B-1%7D%7D%29%5B%5Cfrac%7BT_2-350%7D%7B350T_2%7D%5D)
![In({0.639})=(\frac{34.4*10^3}{8.314K^{-1}})[\frac{T_2-350}{350T_2}]](https://tex.z-dn.net/?f=In%28%7B0.639%7D%29%3D%28%5Cfrac%7B34.4%2A10%5E3%7D%7B8.314K%5E%7B-1%7D%7D%29%5B%5Cfrac%7BT_2-350%7D%7B350T_2%7D%5D)
![- 0.4479 = 41317.599 [\frac{T_2-350}{350T_2} ]K](https://tex.z-dn.net/?f=-%200.4479%20%3D%2041317.599%20%5B%5Cfrac%7BT_2-350%7D%7B350T_2%7D%20%5DK)
![-\frac{0.4479}{4137.599} = [\frac{T_2-350}{350T_2} ]](https://tex.z-dn.net/?f=-%5Cfrac%7B0.4479%7D%7B4137.599%7D%20%3D%20%5B%5Cfrac%7BT_2-350%7D%7B350T_2%7D%20%5D)
![- 1.0825118*10^{-4} = [\frac{T_2-350}{350T_2} ]](https://tex.z-dn.net/?f=-%201.0825118%2A10%5E%7B-4%7D%20%3D%20%5B%5Cfrac%7BT_2-350%7D%7B350T_2%7D%20%5D)






∴ the boiling point of CH3COOC2H5 when the external pressure is 0.639 atm is <u>337.22</u> K.
M1V1=M2V2 M is the molarity and V is the volume.