Ask question

Ask question

All categories

2 years ago

5

Water is leaking out of an inverted conical tank at a rate of13400cubic centimeters per min at the same time that water is being

pumped into the tank at a constant rate. The tank has height8meters and the diameter at the top is6meters. If the water level is rising at a rate of24centimeters per minute when the height of the water is5meters, find the rate at which water is being pumped into the tank in cubic centimeters per minute.

1 answer:

scoundrel [369]2 years ago

4 0

9514 1404 393

Answer:

2,664,118.8 cm³/min

Step-by-step explanation:

The diameter at the water level of 5 m is (5/8)(6 m) = 3.75 m, so the area of the water surface is ...

A = (π/4)d² = (π/4)(3.75 m)² ≈ 11.044662 m²

When rising at the rate of 24 cm/min, the volume is increasing at the rate ...

(110,446.62 cm²)(24 cm/min = 2,650718.8 cm³/min

The input volume must be sufficient to accommodate this increase as well as the leakage. Then the input volume is ...

2,650718.8 cm³/min + 13,400 cm³/min = 2,664,118.8 cm³/min

You might be interested in

5(m+4)=-2(-4-m)+3<br> help please

Degger [83]

Answer:

m = -3

Step-by-step explanation:

5m + 20 = 8 + 2m +3

5m + 20 = 11 +2m

3m + 20 = 11

3m = -9

m = -3

3 0

3 years ago

Another Quick Question, True or false: The Intersection of two rays creates two pairs of vertical angles and four pairs of suppl

andrey2020 [161]

Answer:

True

Step-by-step explanation:

3 0

2 years ago

A sporting goods store sold 30% of the baseball bats in stock. If they had 420 bats in stock, how many did they sell?

Tema [17]

Answer:they sold 126 bats

Step-by-step explanation:

30/100= 3/10

3/10x420=3x42=126

6 0

3 years ago

lions [1.4K]

Answer:

$1 \to 22 \to 0.176$

$2 \to 13 \to 0.104$

$3 \to 18 \to 0.144$

$4 \to 29 \to 0.232$

$5 \to 37 \to 0.296$

$6 \to 6 \to 0.048$

Step-by-step explanation:

Given

$n = 125$

See attachment for proper table

Required

Complete the table

Experimental probability is calculated as:

$Pr = \frac{Frequency}{n}$

We use the above formula when the frequency is known.

For result of roll 2, 4 and 6

The frequencies are 13, 29 and 6, respectively

So, we have:

$Pr(2) = \frac{13}{125} = 0.104$

$Pr(4) = \frac{29}{125} = 0.232$

$Pr(6) = \frac{6}{125} = 0.048$

When the frequency is to be calculated, we use:

$Pr = \frac{Frequency}{n}$

$Frequency = n * Pr$

For result of roll 3 and 5

The probabilities are 0.144 and 0.296, respectively

So, we have:

$Frequency(3) = 125 * 0.144 = 18$

$Frequency(5) = 125 * 0.296 = 37$

For roll of 1 where the frequency and the probability are not known, we use:

$Total \ Frequency = 125$

So:

Frequency(1) added to others must equal 125

This gives:

$Frequency(1) + 13 + 18 + 29 + 37 + 6 = 125$

$Frequency(1) + 103 = 125$

Collect like terms

$Frequency(1) =- 103 + 125$

$Frequency(1) =22$

The probability is then calculated as:

$Pr(1) = \frac{22}{125}$

$Pr(1) = 0.176$

So, the complete table is:

$1 \to 22 \to 0.176$

$2 \to 13 \to 0.104$

$3 \to 18 \to 0.144$

$4 \to 29 \to 0.232$

$5 \to 37 \to 0.296$

$6 \to 6 \to 0.048$

5 0

3 years ago

A coin is tossed 11 times. a) How many different outcomes are possible? b) How many different outcomes have exactly 8 heads? c)

larisa86 [58]

Answer:

a) 2048

b)164

c)54

d) 11

Step-by-step explanation:

a) A coin has two faces.

Outcome possible =2^11= 2048

b) 8 heads possible outcome = 11!/8!3! = 3971688/241/920= 164 ways

c)2 heads outcome= 11!/2!8!= 39716800/725760=54

d) 7 heads= 11!/7!6! =39716800/3628800 = 11

5 0

3 years ago

Read 2 more answers