Answer:
public class print{
public static void fillArray(int[] arr, int initialValue){
int n = arr.length;
for(int i=0;i<n;i++){
arr[i] = initialValue++;
}
for(int i=0;i<n;i++){
System.out.print(arr[i]+" ");
}
}
public static void main(String []args){
int[] array = new int[5];
int initialValue =3;
fillArray(array,initialValue);
}
}
Explanation:
Create the function with two parameter first is array and second is integer.
Then, declare the variable and store the size of array.
Take the for and fill the array from the incremented value of initialValue by 1 at every run of loop.
After loop, print the element of the array.
Create the main function which is used for calling the function and also declare the array with size 5 and initialValue with 3. After that, call the function with this argument.
Answer:
#include <iostream>//including libraries
using namespace std;
int main()
{
int arr[6] = { 0,1,2,3,4,5 };//make sure size of arr is 1 less than secArr
int secArr[7];//second array (1 element bigger)
for (int i = 0;i < 6;i++)//looping through each element (6 times)
{
secArr[i + 1] = arr[i];//transferring elements to second array and shifting by 1 cell
cout << secArr[i + 1] << endl;//printing elements of second array
}
return 0;//terminating program
}
Explanation:
The array size can range from any number. just make sure to keep arr one less than secArr. This is because we need the room for the extra element. This task is to help you understand how array work and how to parse through them using loops. For loops are the best for this task because even if you think intuitively, they work for as long as there are items in the array. and you can define the size yourself.
Answer:
"double result=6.759;" is the correct answer for the above question.
Explanation:
- In c-programming language, the double is a data type which stores the decimal value up to 6 decimal point.
- This data type takes 8 bytes space in memory when it is used in the c-programming language.
- When the user wants to declare the double data type, then he should need to declare by the help of the following syntax-- double variable_name_or _identifier_name;
- When the user wants to declare the double data type and initialize the value on its then he can do this with the help of the following syntax--double variable_name_or _identifier_name= value_which_needs_to_store;
- The above question asked the one-line statement which declares the result variable of double data type and initializes the "6.759" value on its then he can do this by the help of "double result=6.759;" statement which is described above. Hence the answer is "double result=6.759;".
Answer:
A unique identifier for a wireless subscriber
