The combustion of an organic compound is mostly written as,
CaHbOc + O2 --> CO2 + H2O
where a, b, and c are supposed to be the subscripts of the elements C, H, and O in the compound. Determining the number of moles of C and H in the product which is the same as that in the compound,
(Carbon, C) : (561 mg) x (12/44) = 153 mg x (1 mmole/12 mg) = 12.75
(Hydrogen, H) : (306 mg) x (2/18) = 34 mg x (1 mmole/1 mg) = 34
Calculating for amount of O in the sample,
(oxygen, O) = 255 - 153 mg - 34 mg = 68 mg x (1mmole/16 mg) = 4.25
The empirical formula is therefore,
C(51/4)H34O17/4
C3H8O1
The molar mass of the empirical formula is 60. Therefore, the molecular formula of the compound is,
C9H24O3
Answer: Ok I think The SI base unit for amount of substance is the mole. 1 mole is equal to 1 moles Carbon, or 12.0107 grams. Note that rounding errors may occur, so always check the results. Use this page to learn how to convert between moles Carbon and gram. 12 grams
This means that the atomic mass or atomic weight (12 grams) of carbon is equal to exactly 1 mole of carbon.
hope this helps have a awesome night/day❤️✨
Explanation:
Sometimes negative sometimes positive, your answer is B!
Answer:2NaF is the correct one. It’s a simple combination and can be be split with relative ease
Explanation:
Answer: 4 molL-1
Explanation:
Detailed solution is shown in the image attached. The number of moles of NaCl is first obtained. Since the molarity must be in units of molL-1, the volume is divided by 1000 and the formula stated in the solution is applied and the answer is given to one significant figure.
