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finlep [7]
3 years ago
14

WILL MARK BRAINLIEST! Given ΔABC : ΔDEF, find x. 10 14 27 12

Mathematics
2 answers:
oksano4ka [1.4K]3 years ago
6 0

Answer:

x=12

Step-by-step explanation:

If the triangles are similar:

x/8=18/12

x/8=1.5

x=12

Nezavi [6.7K]3 years ago
6 0

Answer:

12.

Step-by-step explanation:

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AveGali [126]

Answer:

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Read 2 more answers
A friend of mine is giving a dinner party. His current wine supply includes 9 bottles of zinfandel, 10 of merlot, and 12 of cabe
e-lub [12.9K]

Answer:

Step-by-step explanation:

From the given information:

The total number of wine = 9 + 10 + 12 = 31

(1)

The number of distinct sequences used for serving any five wines can be estimated by using the permutation of the number of total wines with the number of wines served.

i.e

= ^{31}P_5

=\dfrac{31!}{(31-5)!}

=\dfrac{31!}{(26)!}

=\dfrac{31\times 30\times 29\times 28\times 27\times 26!}{(26)!}

= 20389320

(2)

If the first two wines served = zinfandel and the last three is either merlot or cabernet;

Then, the no of ways we can achieve this is:

= ^9P_2\times ^{22}P_3

= \dfrac{9!}{(9-2)!}\times \dfrac{22!}{(22-3)!}

= \dfrac{9!}{(7)!}\times \dfrac{22!}{(19)!}

= \dfrac{9*8*7!}{(7)!}\times \dfrac{22*21*20*19!}{(19)!}

= 665280

(3)

The probability that no zinfandel is served is computed as follows:

Total wines (with zinfandel exclusion) = 31 - 9 = 22

Now;

the required probability is:

= \dfrac{^{22}P_5 }{^{31}P_5}

= \dfrac{\dfrac{22!}{(22-5)!} } {\dfrac{31!}{(31-5)!} }

= \dfrac{\dfrac{22!}{17!} } {\dfrac{31!}{(26)! }}

= \dfrac{(\dfrac{22*21*20*19*18*17!}{17!})} {(\dfrac{31*30*29*28*27*26!}{(26)! })}

= 0.1549

≅ 0.155

4 0
3 years ago
Mr. Anderson doctor has advised him to go on a diet he must reduce his caloric intake by 15% he currently eats 2800 calories per
alina1380 [7]
15 percent of 2800 is 420. All you would do is take 2800 minus 420 which is equal to 2380 calories
3 0
3 years ago
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