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mixer [17]
3 years ago
8

Please help its due today and show all of your work please. I will give you brainliest if you help me do it right

Mathematics
2 answers:
devlian [24]3 years ago
5 0

Step-by-step explanation:

elimination of x:

-6x +5y = 1

6x + 4y = -10

___________+

9y = -9

y = -9/9 = -1

elimination of y:

-24x +20y = 4

30x + 20y = -50

_____________-

-54x = 54

x = 54/-54 = -1

{ -1, -1}

olya-2409 [2.1K]3 years ago
4 0

\huge{ \mathcal{  \underline{ Answer }\:  \:  ✓ }}

The given equations are :

\longrightarrow - 6x + 5y = 1

\longrightarrow6x + 4y =  - 10

let's add the equations

\longrightarrow\small{ - 6x + 5y +6x + 4y =  1  + ( - 10)}

\longrightarrow9y =  - 9

\longrightarrow y =  - 1

now, let's plug the value of y in first equation :

\longrightarrow - 6x + (5 \times  - 1) = 1

\longrightarrow - 6x  - 5 = 1

\longrightarrow - 6x = 6

\longrightarrow x =  - 1

_________________________

\mathrm{ ☠ \: TeeNForeveR \:☠ }

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Como construir el numero 1,000​
mars1129 [50]

Answer:

500+500 = 1000

100*10 = 1000

10^3 = 1000

10*10*10 = 1000

Hope i helped

<h2><em>DaniElSabiondo</em></h2>
5 0
3 years ago
CHECK ANSWERS -
Tju [1.3M]
Both are correct.

Good job!
6 0
3 years ago
Write an equation in standard form using integers <br><br> Y= - x<br> —<br> 5
kykrilka [37]

Answer:

x + y = - 5

Step-by-step explanation:

The equation of a line in standard form is

Ax + By = C ( A is a positive integer and B, C are integers )

Given

y = - x - 5 ( add x to both sides )

x + y = - 5 ← in standard form

8 0
3 years ago
Find the equation of a line that is perpendicular to y = 3x – 5 and passes through the point (1, -3).
Svetradugi [14.3K]

keeping in mind that perpendicular lines have negative reciprocal slopes, let's check for the slope of the equation above

\begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array}\qquad \qquad y = \stackrel{\stackrel{m}{\downarrow }}{3}x-5

well then therefore

\stackrel{\textit{perpendicular lines have \underline{negative reciprocal} slopes}} {\stackrel{slope}{3\implies \cfrac{3}{1}} ~\hfill \stackrel{reciprocal}{\cfrac{1}{3}} ~\hfill \stackrel{negative~reciprocal}{-\cfrac{1}{3}}}

so we're really looking for the equation of a line with slope of -1/3 and that passes through (1, -3 )

(\stackrel{x_1}{1}~,~\stackrel{y_1}{-3})\qquad \qquad \stackrel{slope}{m}\implies -\cfrac{1}{3} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{(-3)}=\stackrel{m}{-\cfrac{1}{3}}(x-\stackrel{x_1}{1})\implies y+3=-\cfrac{1}{3}x+\cfrac{1}{3} \\\\\\ y=-\cfrac{1}{3}x+\cfrac{1}{3}-3\implies y=-\cfrac{1}{3}x-\cfrac{8}{3}

6 0
2 years ago
Through (0,2) and (4,1) write the slope intercept form of the equation of the line
lesya692 [45]

Answer:

y= -1/4x+2

Step-by-step explanation:

use the slope formula to get the slope: y2-y1/x2-x1 or 1-2/4-0 subtract to get -1/4 that is the m(slope)*x in y=mx+b now for b it is the point in which x=0 so the first point has x=0 and it's y is 2 so b is 2. put it together to get y=-1/4x+2

6 0
3 years ago
Read 2 more answers
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