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kicyunya [14]
3 years ago
10

The Valence electrons determine an atom's ?

Physics
1 answer:
olga55 [171]3 years ago
3 0

Answer:

The valence electrons determine an atom's reactivity.

Explanation:

The valence electrons is the electrons on the most outer layer of an atom. The higher the number of valence electrons, the bigger the reactivity of the atom. This means that when that atom is put with another substance and it reacts, it would react in a much more violent way than another atom with lower valence electrons.

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How is kinetic energy related to the distance
astra-53 [7]

Kinetic energy =

1/2 (mass) • (velocity squared).

I don't see distance in that formula anywhere, so they're not related.

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Even if it is wrong, why is a hypothesis important?
Setler79 [48]
So you can have a understanding of what you are doing and figure out your overall goal
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2 years ago
Which of these characteristics did all of the five waves of immigrants have in common A. They all had the same political beliefs
timofeeve [1]
I am pretty sure it is c
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3 years ago
An aeroplane accelerates from rest to 65 m/s for take-off. It travels for
Virty [35]

Answer:

1.76m/s²

Explanation:

Given parameters:

Initial velocity  = 0m/s

Final velocity  = 65m/s

Distance traveled  = 1200m

Unknown:

Acceleration  = ?

Solution:

This is linear velocity and we apply the appropriate motion equation to solve this problem.

      V²  = U² + 2as

S is the distance

u is the initial velocity

V is the final velocity

a is the acceleration

Now, insert the parameters and solve;

             65²  =  0² + 2 x a x 1200

             4225 = 2400a

                  a  = 1.76m/s²

5 0
3 years ago
A length change 0.08 m will occur for an object that is L= 56 m long. If the coefficient of thermal expansion is5.3 x 10 /C and
ArbitrLikvidat [17]

Answer:

Increase in temperature =  269.54 °C

Explanation:

We have equation for thermal expansion

          ΔL = LαΔT

Change in length, ΔL = 0.08 m

Length, L = 56 m

Coefficient of thermal expansion, α = 5.3 x 10⁻⁶ °C⁻1

Change in temperature, ΔT = T - 253

Substituting

          0.08 = 56 x 5.3 x 10⁻⁶ x (T - 253)

         (T - 253) = 269.54

           T = 522.54 °C

Increase in temperature =  269.54 °C      

4 0
2 years ago
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