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2 years ago

10

The Valence electrons determine an atom's ?

1 answer:

olga55 [171]2 years ago

3 0

Answer:

The valence electrons determine an atom's reactivity.

Explanation:

The valence electrons is the electrons on the most outer layer of an atom. The higher the number of valence electrons, the bigger the reactivity of the atom. This means that when that atom is put with another substance and it reacts, it would react in a much more violent way than another atom with lower valence electrons.

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Which produces more gravitational force on your textbook: you or the earth?

Yuri [45]

The earth obviously because it is on Earth like we are and it has the same gravital properties. It falls when you drop it and rises when you pick it up

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3 years ago

You're driving a vehicle of mass 1350 kg and you need to make a turn on a flat road. The radius of curvature of the turn is 71 m

sergey [27]

Answer:

$v=12.65\ m.s^{-1}$

Explanation:

Given:

mass of vehicle, $m=1350\ kg$

radius of curvature, $r=71\ m$

coefficient of friction, $\mu=0.23$

<u>During the turn to prevent the skidding of the vehicle its centripetal force must be equal to the opposite balancing frictional force:</u>

$m.\frac{v^2}{r} =\mu.N$

where:

$\mu=$ coefficient of friction

$N=$ normal reaction force due to weight of the car

$v=$ velocity of the car

$1350\times \frac{v^2}{71} =0.23\times (1350\times 9.8)$

$v=12.65\ m.s^{-1}$ is the maximum velocity at which the vehicle can turn without skidding.

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3 years ago

Which of the following is NOT a

Liula [17]

Answer:B

Explanation:

6 0

3 years ago

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A 5 kg ball moving to the right at a speed of 6 m/s strikes another 4 kg ball moving to the left at 5 m/s. What is the velocity

Vinil7 [7]

Answer:

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Explanation:

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2 years ago

You drive a beat-up pickup truck along a straight road for 8.4 km at 70 km/h, at which point the truck runs out of gasoline and

andreev551 [17]

Answer:

v_avg = 37 km/h

Explanation:

To find the average velocity in the complete trajectory you use the following formula:

$v_{avg}=\frac{v_1+v_2}{2}$ ( 1 )

v1: velocity in the first part of the trajectory = 70 km/h

v2: velocity in the second part of the trajectory = ?

You calculate v2 by using the following equation for a motion with constant velocity:

$v_2=\frac{2.0km}{30min}*\frac{60min}{1h}=4\frac{km}{h}$

you replace the values of v1 and v2 in (1) and you obtain:

$v_{avg}=\frac{70km/h+4km/h}{2}=37\frac{km}{h}$

hence, the average velocity is 37 km/h

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2 years ago

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