Answer:
16.405m/s
Explanation:
Given, initial velocity = u = 1.93m/s, acceleration = a = 0.750m/s2, time = t = 19.3s, final velocity = v= ?
Using the first equation of linear motion,
v = u + at
v = 1.93 + 0.750 x 19.3
v = 1.93 + 14.475
v = 16.405m/s
Answer:
Explanation:
given
initial velocity u = 4.45m/s
Height = 0.6m
g = 9.8m/s²
Required
final velocity v
Using the equation of motion;
v² = u²-2gH (upward motion of the fish makes g to be negative)
v² = 4.45²-2(9.8)(0.6)
v² = 19.8025-11.76
v² = 8.0425
v = 2.84 m/s
Hence the speed of the fish as it passes a point 0.6 m above the water is 2.84m/s
To get the time, we will use the formula
v = u - gt
2.84 = 4.45 - 9.8t
2.84-4.45 = -9.8t
-1.61 = -9.8t
t = 1.61/9.8
t = 0.164secs
Hence the time taken is 0.164secs
Answer is C, one student has more mass, therefore more inertia.
Answer: 270 km
Explanation:
3 cm/80 km :: 10 cm/(x)km
cross multiply
3x = 80(10)
x = 800/3 = 266.66666... ≈ 270 km
